Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 6)
6.
In a race of 200 m, A can beat B by 31 m and C by 18 m. In a race of 350 m, C will beat B by:
Answer: Option
Explanation:
A : B = 200 : 169.
A : C = 200 : 182.
| C | = |  |
C | x | A |  |
= | |
182 | x | 200 | |
= 182 : 169. |
| B | A | B | 200 | 169 |
When C covers 182 m, B covers 169 m.
| When C covers 350 m, B covers | |
169 | x 350 | m |
= 325 m. |
| 182 |
Therefore, C beats B by (350 - 325) m = 25 m.
Discussion:
20 comments Page 2 of 2.
Rahul said:
7 years ago
The distance between C and B is 13 m when C is at distance 182 m (C is 18 m behind A and A has finished 200 m).
Therefore, its 13 m for 182 m race.
(13/182) * 350 for 350 m race = 25 m.
Therefore, its 13 m for 182 m race.
(13/182) * 350 for 350 m race = 25 m.
Mir Rokon Uddin said:
8 years ago
200 - 31=169,
2000 -18 = 182,
If C goes 182 then B goes 169.
So if C goes 350 then B goes 325.
So C will beat B by (350-325) = 25m.
2000 -18 = 182,
If C goes 182 then B goes 169.
So if C goes 350 then B goes 325.
So C will beat B by (350-325) = 25m.
Ashish said:
8 years ago
As A -> 200.
B -> 200 - 31 = 169.
C -> 200 - 18 = 182.
If C covers 182m then B covers 169m so the ratio is B : C = 169 : 182.
As in 350m, let the distance be x then,
200/(182 - 169) = 350/x,
x = 91/4,
x = 22.75.
B -> 200 - 31 = 169.
C -> 200 - 18 = 182.
If C covers 182m then B covers 169m so the ratio is B : C = 169 : 182.
As in 350m, let the distance be x then,
200/(182 - 169) = 350/x,
x = 91/4,
x = 22.75.
Harsh said:
9 years ago
How did you get @Aishi, C-B = 6? as C-B =13, But anyway answer comes to be 22.75.
Aishi said:
10 years ago
A-B = 31 since A beats B by 31 m.
A-C = 18 since A beats C by 18 m.
So C-B = 6 i.e C beats B by 6 m when rate is 200 m.
So when race is 350 m it should be (6/200)*350 = 22.75 m.
A-C = 18 since A beats C by 18 m.
So C-B = 6 i.e C beats B by 6 m when rate is 200 m.
So when race is 350 m it should be (6/200)*350 = 22.75 m.
Sukriti said:
1 decade ago
But the race finishes as A covers 350 distance?
P.Vijaya kumar said:
1 decade ago
@Sunita.
Eg: Assume A's speed is twice than B...if A reached 100 km ,that time B reached only 50km.
Ratio of A:B=2:1
In 300 km race ,B reached only 150km,when A reach the goal.
How is it possible:
B's distance when a reached the goal=(1/2)*300=150
Are u agree that.
Same as the ratio of A:B =182:169
So B's distance=(169/182)*350=325...
I think is correct.If any flaw is there,please correct me.
Eg: Assume A's speed is twice than B...if A reached 100 km ,that time B reached only 50km.
Ratio of A:B=2:1
In 300 km race ,B reached only 150km,when A reach the goal.
How is it possible:
B's distance when a reached the goal=(1/2)*300=150
Are u agree that.
Same as the ratio of A:B =182:169
So B's distance=(169/182)*350=325...
I think is correct.If any flaw is there,please correct me.
Smritimay said:
1 decade ago
A can beat B by 31, then (total distance-A beat B) = 200-31 = 169.
Sunita said:
1 decade ago
From where 325 came. Multiplication result wrong.
Xyz said:
1 decade ago
From Where did you get the 200 and 169
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