# Aptitude - Races and Games - Discussion

Discussion Forum : Races and Games - General Questions (Q.No. 6)

6.

In a race of 200 m, A can beat B by 31 m and C by 18 m. In a race of 350 m, C will beat B by:

Answer: Option

Explanation:

A : B = 200 : 169.

A : C = 200 : 182.

C | = | C | x | A | = | 182 | x | 200 | = 182 : 169. | ||||

B | A | B | 200 | 169 |

When C covers 182 m, B covers 169 m.

When C covers 350 m, B covers | 169 | x 350 | m | = 325 m. | |

182 |

Therefore, C beats B by (350 - 325) m = 25 m.

Discussion:

20 comments Page 2 of 2.
Rahul said:
7 years ago

The distance between C and B is 13 m when C is at distance 182 m (C is 18 m behind A and A has finished 200 m).

Therefore, its 13 m for 182 m race.

(13/182) * 350 for 350 m race = 25 m.

Therefore, its 13 m for 182 m race.

(13/182) * 350 for 350 m race = 25 m.

Mir Rokon Uddin said:
7 years ago

200 - 31=169,

2000 -18 = 182,

If C goes 182 then B goes 169.

So if C goes 350 then B goes 325.

So C will beat B by (350-325) = 25m.

2000 -18 = 182,

If C goes 182 then B goes 169.

So if C goes 350 then B goes 325.

So C will beat B by (350-325) = 25m.

Ashish said:
8 years ago

As A -> 200.

B -> 200 - 31 = 169.

C -> 200 - 18 = 182.

If C covers 182m then B covers 169m so the ratio is B : C = 169 : 182.

As in 350m, let the distance be x then,

200/(182 - 169) = 350/x,

x = 91/4,

x = 22.75.

B -> 200 - 31 = 169.

C -> 200 - 18 = 182.

If C covers 182m then B covers 169m so the ratio is B : C = 169 : 182.

As in 350m, let the distance be x then,

200/(182 - 169) = 350/x,

x = 91/4,

x = 22.75.

Harsh said:
8 years ago

How did you get @Aishi, C-B = 6? as C-B =13, But anyway answer comes to be 22.75.

Aishi said:
9 years ago

A-B = 31 since A beats B by 31 m.

A-C = 18 since A beats C by 18 m.

So C-B = 6 i.e C beats B by 6 m when rate is 200 m.

So when race is 350 m it should be (6/200)*350 = 22.75 m.

A-C = 18 since A beats C by 18 m.

So C-B = 6 i.e C beats B by 6 m when rate is 200 m.

So when race is 350 m it should be (6/200)*350 = 22.75 m.

Sukriti said:
1 decade ago

But the race finishes as A covers 350 distance?

P.Vijaya kumar said:
1 decade ago

@Sunita.

Eg: Assume A's speed is twice than B...if A reached 100 km ,that time B reached only 50km.

Ratio of A:B=2:1

In 300 km race ,B reached only 150km,when A reach the goal.

How is it possible:

B's distance when a reached the goal=(1/2)*300=150

Are u agree that.

Same as the ratio of A:B =182:169

So B's distance=(169/182)*350=325...

I think is correct.If any flaw is there,please correct me.

Eg: Assume A's speed is twice than B...if A reached 100 km ,that time B reached only 50km.

Ratio of A:B=2:1

In 300 km race ,B reached only 150km,when A reach the goal.

How is it possible:

B's distance when a reached the goal=(1/2)*300=150

Are u agree that.

Same as the ratio of A:B =182:169

So B's distance=(169/182)*350=325...

I think is correct.If any flaw is there,please correct me.

Smritimay said:
1 decade ago

A can beat B by 31, then (total distance-A beat B) = 200-31 = 169.

Sunita said:
1 decade ago

From where 325 came. Multiplication result wrong.

Xyz said:
1 decade ago

From Where did you get the 200 and 169

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