Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 1)
1.
In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C:
Answer: Option
Explanation:
A : B = 100 : 90.
A : C = 100 : 72.
| B : C = | B | x | A | = | 90 | x | 100 | = | 90 | . |
| A | C | 100 | 72 | 72 |
When B runs 90 m, C runs 72 m.
| When B runs 100 m, C runs |  |
72 | x 100 |  m |
= 80 m. |
| 90 |
B can give C 20 m.
Discussion:
43 comments Page 3 of 5.
Ammu said:
8 years ago
Please anyone explain this in simple way.
MOHANAGIRI said:
7 years ago
@Raja.
Clear explanation. Thanks for that.
Clear explanation. Thanks for that.
Kalaivani said:
1 decade ago
Can any one please explain logic clearly. How and why 72/90?
Sanju said:
1 decade ago
When we took ratio between 100:90 we get 10. So they took 90 insted of 10. I hope you understand.
Gaurav said:
1 decade ago
100-10=90, 100-28=72;
Because according to question A can gives B 10m and A can gives C 28m. I try my best to solve your problem.
Because according to question A can gives B 10m and A can gives C 28m. I try my best to solve your problem.
Shameer said:
1 decade ago
Why we not use A:B:C=90:X:72 ?
Saru said:
1 decade ago
Why we use B/AxA/c here?
Bharath ks said:
1 decade ago
Can anyone explain it easily please ?
Prasanna said:
1 decade ago
Why not going the race at which the question says? That is when finish the game B is 18m ahead of C.
Manojit said:
1 decade ago
Because it is same race. They must complete same distance so when B has completed 100 m. He will give C 20m.
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