Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 1)
1.
In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C:
Answer: Option
Explanation:
A : B = 100 : 90.
A : C = 100 : 72.
| B : C = | B | x | A | = | 90 | x | 100 | = | 90 | . |
| A | C | 100 | 72 | 72 |
When B runs 90 m, C runs 72 m.
| When B runs 100 m, C runs |  |
72 | x 100 |  m |
= 80 m. |
| 90 |
B can give C 20 m.
Discussion:
43 comments Page 2 of 5.
Aarti said:
10 years ago
How to solve this problems in easiest way?
Abhishek kushwaha said:
1 decade ago
In a 100 m race, A can give B 10 m, It means A:B=100:90.....equation (1).
In a 100 m race, A can give C 28 m, It means A:C=100:72....equation (2).
In a 100 m race, B can give C=?
{Dividing Equation (1) and Equation (2) we get}.
B:C=90:72 or B:C=5:4 (After Dividing numerator and denominator by 18).
Or B:C=100:80 (After Multiplying numerator and denominator by 20).
In the same race B can give C=20[ANS].
In a 100 m race, A can give C 28 m, It means A:C=100:72....equation (2).
In a 100 m race, B can give C=?
{Dividing Equation (1) and Equation (2) we get}.
B:C=90:72 or B:C=5:4 (After Dividing numerator and denominator by 18).
Or B:C=100:80 (After Multiplying numerator and denominator by 20).
In the same race B can give C=20[ANS].
Aakriti said:
9 years ago
Thanks, @Abhishek Kushwaha.
Manisha said:
9 years ago
Thank you all for helping me.
Akhil kondaparva said:
9 years ago
A defeats B by 10m i.e. if A runs 100m then B runs 90m.
A defeats c by 28m i.e. if A runs 100m then C runs 72m.
If B = 90 then C = 72.
If B = 100 then C = ? (cross multiply).
=> C = (72 x 100) / 90 = 80m.
So, if B = 100 C = 80.
ie=> B defeats C by 20 metres.
A defeats c by 28m i.e. if A runs 100m then C runs 72m.
If B = 90 then C = 72.
If B = 100 then C = ? (cross multiply).
=> C = (72 x 100) / 90 = 80m.
So, if B = 100 C = 80.
ie=> B defeats C by 20 metres.
Dynamo said:
9 years ago
We have to compare between B & C.
If B goes 90.
C goes 72.
To be 100 we have to multiply by 100 and divide by 90.
90 * 100/90 ------> 72 * 100/90.
100 ------> 80.
So, B can give C = 100 - 80 = 20.
If B goes 90.
C goes 72.
To be 100 we have to multiply by 100 and divide by 90.
90 * 100/90 ------> 72 * 100/90.
100 ------> 80.
So, B can give C = 100 - 80 = 20.
Manoj said:
9 years ago
Given A 100, B 10, C 28.
A gives B means 100 - 10 = 90 = B.
A gives C means 100 - 28 = 72 = C.
A : B = 100 : 90.
A : C = 100 : 72.
B : C = 90 : 72 -------> 90/72 = B/C.
Consider given one as 100.
B gives C is
B : C = 100 : 72/90.
C/B = 72/90 * 100 = 80m.
A gives B means 100 - 10 = 90 = B.
A gives C means 100 - 28 = 72 = C.
A : B = 100 : 90.
A : C = 100 : 72.
B : C = 90 : 72 -------> 90/72 = B/C.
Consider given one as 100.
B gives C is
B : C = 100 : 72/90.
C/B = 72/90 * 100 = 80m.
Sayeeda said:
8 years ago
Thank you for your explanation @Akhil.
Ramesh said:
8 years ago
I am not getting it.
At last how the answers came as 20? please explain.
At last how the answers came as 20? please explain.
Jayasree said:
8 years ago
Does anyone know how can we solve this question by having the difference in distance values only( i.e, using 10 and 28)?
Please tell me.
Please tell me.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers