# Aptitude - Races and Games - Discussion

Discussion Forum : Races and Games - General Questions (Q.No. 1)
1.
In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C:
18 m
20 m
27 m
9 m
Explanation:

A : B = 100 : 90.

A : C = 100 : 72.

 B : C = B x A = 90 x 100 = 90 . A C 100 72 72

When B runs 90 m, C runs 72 m.

 When B runs 100 m, C runs 72 x 100 m = 80 m. 90 B can give C 20 m.

Discussion:
43 comments Page 1 of 5.

Aarushi said:   4 months ago
A finished 100m.
At that time,
B is 10m less than A, so B is 100-10=90.
C is 28m less than A, so C is 100-28=72.

The difference b/w in B and C is,
90-72 = 18.

When B is 90m then the difference is 18m.
When B is 1m the difference is 18/90 = 0.2m.
When B is 100m the difference is 0.2 * 100 = 20m.
At that time C will be 80m.
Ans is 20m.
(5)

Mouni said:   1 year ago
Can anyone explain this in a simple way?
(3)

Ngawa said:   3 years ago
Difference between B and C
28 - 10 =18.
Now,
18 /90 * 100= 20.
Thus give 20m in 100 game.
(10)

Gauri said:   3 years ago
Thank you for the explanation @Akhil.
(1)

Aksh said:   5 years ago
A gives B 10m means A beats B by 10m, A wins the race, by completing 100m, ie B will be at 10.
(2)

Prince Priyadarshi said:   5 years ago
@All.

The solution is;

In same time A,B and C travel 100,90,72 meters respectively hence we can write:
100:VA = 90:VB = 72:VC where VA,VB,VC are velocities of A, B, C respectively.
Hence;
VB:VC = 90x:72x that means time taken by B to travel 100m is tb= 100/90x.
In this time C travel ( 100/90x)*72x = 80 m implies B gives C by 20m.
(1)

MOHANAGIRI said:   5 years ago
@Raja.

Clear explanation. Thanks for that.

Raja said:   6 years ago
A finished 100m.
At that time.
B is 10m less than A, so B is 90.
C is 28m less than A, so C is 72.
The difference b/w in B and C is.
90-72 = 18.
When B is 90m then the difference is 18m.
When B is 1m the difference is 18/90=0.2m.
When B is 100m the difference is 0.2 * 100=20m.
At that time C will be 80m.
Ans is 20m.
(6)

Siddharth said:   6 years ago
Here, give indicates the distance that participants overtake each other.

So, A beats B by 10m in a 100m race indicates A finishes 100m whereas B finishes 10m behind A in the same time ie.) 90m.

Similiarly, A beats C by 28m indicates C covers 72m in the same time where A finishes 100m.
Now ratio of distance covered in a given time by B and C remains same ie.) 90:72 ie.) 5:4.

When, B covers 100m in a given time, C covers only 80 in the same time. So B beats C by a distance of 20m.
(2)

Anandu said:   6 years ago
@Ammu

I think throughout the race a, b&c have respective constant velocities.
That being said this problem can easily be solved using the concept of ratios.

Question is to find the distance btw b&c at the end of the race(when b reaches 100m).
It is given separation btw b & c when b reaches 90m is 18 (ie 90-72).
So, when b reaches 1m mark the Seperation btw them is simply 18÷90=1/5
When b reaches 100m ie end of the race the seperation is (1/5) * 100. =. 20.

I hope it is clear now.
(1)