Aptitude - Races and Games - Discussion

A can give 10 means A can lead B by 10 meter. That's A can give a lead of 10 meter. Got t @Arun.

Melvin its just not distance calculation to simply difference the distance. Here change in velocity of the players maters. For example if you just subtract the distance means B and C are running in same velocity right?

If so how would B can beat C in the race in the beginning? Got t so there is a velocity change in players that's what you are calculating unstintingly.

In a 100 m race, A can give B 10 m, It means A:B=100:90.....equation (1).

In a 100 m race, A can give C 28 m, It means A:C=100:72....equation (2).

In a 100 m race, B can give C=?

{Dividing Equation (1) and Equation (2) we get}.

B:C=90:72 or B:C=5:4 (After Dividing numerator and denominator by 18).

Or B:C=100:80 (After Multiplying numerator and denominator by 20).

In the same race B can give C=20[ANS].

How to solve this problems in easiest way?

Thanks, @Abhishek Kushwaha.

Thank you all for helping me.

A defeats B by 10m i.e. if A runs 100m then B runs 90m.

A defeats c by 28m i.e. if A runs 100m then C runs 72m.

If B = 90 then C = 72.

If B = 100 then C = ? (cross multiply).

=> C = (72 x 100) / 90 = 80m.

So, if B = 100 C = 80.

ie=> B defeats C by 20 metres.

We have to compare between B & C.

If B goes 90.

C goes 72.

To be 100 we have to multiply by 100 and divide by 90.

90 * 100/90 ------> 72 * 100/90.

100 ------> 80.

So, B can give C = 100 - 80 = 20.

Given A 100, B 10, C 28.

A gives B means 100 - 10 = 90 = B.
A gives C means 100 - 28 = 72 = C.
A : B = 100 : 90.
A : C = 100 : 72.

B : C = 90 : 72 -------> 90/72 = B/C.


Consider given one as 100.
B gives C is

B : C = 100 : 72/90.
C/B = 72/90 * 100 = 80m.

Thank you for your explanation @Akhil.

They are asking when B is at 100 m, where is C?

Consider A need x seconds to reach at 100m.

Velocity of A is 100/x.

Given that when A is at 100m, B and C are at 90m and 72m respectively...

So,velocity of B is 90/x (m/sec)
velocity of C is 72/x (m/sec)

Now, For B to reach 100m, 10m again have to run
time required for B to run 10m =10/(90/x) = x/9 sec.
distance covered by C in x/9 sec =(x/9)*(72/x) = 8m.

So when B is at 90+10=100m.
C is at 72+8 = 80m.

B won race by 20m difference with C.