Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 1)
1.
In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C:
Answer: Option
Explanation:
A : B = 100 : 90.
A : C = 100 : 72.
| B : C = | B | x | A | = | 90 | x | 100 | = | 90 | . |
| A | C | 100 | 72 | 72 |
When B runs 90 m, C runs 72 m.
| When B runs 100 m, C runs |  |
72 | x 100 |  m |
= 80 m. |
| 90 |
B can give C 20 m.
Discussion:
43 comments Page 5 of 5.
Ngawa said:
5 years ago
Difference between B and C
28 - 10 =18.
Now,
18 /90 * 100= 20.
Thus give 20m in 100 game.
28 - 10 =18.
Now,
18 /90 * 100= 20.
Thus give 20m in 100 game.
(21)
Mouni said:
3 years ago
Can anyone explain this in a simple way?
(6)
Aarushi said:
2 years ago
A finished 100m.
At that time,
B is 10m less than A, so B is 100-10=90.
C is 28m less than A, so C is 100-28=72.
The difference b/w in B and C is,
90-72 = 18.
When B is 90m then the difference is 18m.
When B is 1m the difference is 18/90 = 0.2m.
When B is 100m the difference is 0.2 * 100 = 20m.
At that time C will be 80m.
Ans is 20m.
At that time,
B is 10m less than A, so B is 100-10=90.
C is 28m less than A, so C is 100-28=72.
The difference b/w in B and C is,
90-72 = 18.
When B is 90m then the difference is 18m.
When B is 1m the difference is 18/90 = 0.2m.
When B is 100m the difference is 0.2 * 100 = 20m.
At that time C will be 80m.
Ans is 20m.
(23)
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