Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 1)
1.
In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C:
Answer: Option
Explanation:
A : B = 100 : 90.
A : C = 100 : 72.
| B : C = | B | x | A | = | 90 | x | 100 | = | 90 | . |
| A | C | 100 | 72 | 72 |
When B runs 90 m, C runs 72 m.
| When B runs 100 m, C runs |  |
72 | x 100 |  m |
= 80 m. |
| 90 |
B can give C 20 m.
Discussion:
43 comments Page 3 of 5.
Aarti said:
10 years ago
How to solve this problems in easiest way?
Abhishek kushwaha said:
1 decade ago
In a 100 m race, A can give B 10 m, It means A:B=100:90.....equation (1).
In a 100 m race, A can give C 28 m, It means A:C=100:72....equation (2).
In a 100 m race, B can give C=?
{Dividing Equation (1) and Equation (2) we get}.
B:C=90:72 or B:C=5:4 (After Dividing numerator and denominator by 18).
Or B:C=100:80 (After Multiplying numerator and denominator by 20).
In the same race B can give C=20[ANS].
In a 100 m race, A can give C 28 m, It means A:C=100:72....equation (2).
In a 100 m race, B can give C=?
{Dividing Equation (1) and Equation (2) we get}.
B:C=90:72 or B:C=5:4 (After Dividing numerator and denominator by 18).
Or B:C=100:80 (After Multiplying numerator and denominator by 20).
In the same race B can give C=20[ANS].
Vichu said:
1 decade ago
A can give 10 means A can lead B by 10 meter. That's A can give a lead of 10 meter. Got t @Arun.
Melvin its just not distance calculation to simply difference the distance. Here change in velocity of the players maters. For example if you just subtract the distance means B and C are running in same velocity right?
If so how would B can beat C in the race in the beginning? Got t so there is a velocity change in players that's what you are calculating unstintingly.
Melvin its just not distance calculation to simply difference the distance. Here change in velocity of the players maters. For example if you just subtract the distance means B and C are running in same velocity right?
If so how would B can beat C in the race in the beginning? Got t so there is a velocity change in players that's what you are calculating unstintingly.
ARUN said:
1 decade ago
What is the meaning of A can give start of 10 meter?
Melvin said:
1 decade ago
How B give C 20? Is we simply check question the right answer is 18 because 28-10=18.
Jklomn said:
1 decade ago
B is 18 meters ahead of C when he is at 90 m, when he will finish the race he will be 20 m ahead.
Diya said:
1 decade ago
It is meter.
Anime said:
1 decade ago
What is m here? Is it meter or minute?
Deepika said:
1 decade ago
A : B = 100 : 90.
A : C = 100 : 72.
So divide both this equation you get C:B = 4:5.
And now we find for same 100 m race so multiply by 5*20=100 because we Find b can give c in same race.
4*20/5*20 = 80/100 = C/B.
So B can give C = 100-80 = 20 answer
A : C = 100 : 72.
So divide both this equation you get C:B = 4:5.
And now we find for same 100 m race so multiply by 5*20=100 because we Find b can give c in same race.
4*20/5*20 = 80/100 = C/B.
So B can give C = 100-80 = 20 answer
Venkat said:
1 decade ago
Can anyone explain it easily please?
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