Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 13)
13.
In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:
Answer: Option
Explanation:
A : B = 100 : 75
B : C = 100 : 96.
 A : C = |
 |
A | x | B |  |
= | |
100 | x | 100 | |
= | 100 | = 100 : 72. |
| B | C | 75 | 96 | 72 |
A beats C by (100 - 72) m = 28 m.
Discussion:
11 comments Page 2 of 2.
Vishal ahire NIPER said:
1 year ago
A:B:C an important ratio,
when, A = 100 then at that time B = 75
when B = 100 then at that time C = 96
so, according to ratio A:B: C = 100:75:X
Let, calculate according to that when,
when B = 100 then C=96 so if B = 75 then C = ?
by cross-calculation we can determine, if
B is 100 = C is 96,
B is 75 = C is X.
X= (75 x 96)/100,
X= 72,
so, if A:B:C = 100:75:72.
The difference between the distance the A and C is (100-72 = 28).
when, A = 100 then at that time B = 75
when B = 100 then at that time C = 96
so, according to ratio A:B: C = 100:75:X
Let, calculate according to that when,
when B = 100 then C=96 so if B = 75 then C = ?
by cross-calculation we can determine, if
B is 100 = C is 96,
B is 75 = C is X.
X= (75 x 96)/100,
X= 72,
so, if A:B:C = 100:75:72.
The difference between the distance the A and C is (100-72 = 28).
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