### Discussion :: Races and Games - General Questions (Q.No.3)

Kriti said: (Dec 3, 2010) | |

Hi, when 3:4 is the ratio of speeds how can we use it as 3m and 4m for A and B resp.? |

Sudheer said: (May 19, 2011) | |

Hi kriti here speed and distance are directly proportinal. If his speed is 10km/hr he cover 10km distance. If speed is 20km/hr he can cover 20 km distance. Thus speed and distance are directly proportinal. So here distance ratios also become3:4. But the time ratio will become4:3 because time and speed are inversly proportinal. |

Vamsi said: (Jul 5, 2011) | |

I didn't understand how it can be 4/3. ? |

Malli said: (Sep 30, 2011) | |

Hai, my dout is same that of vamsi. Why we had taken 4/3 in problem? |

Manojit said: (Feb 9, 2012) | |

While A covers 3 m, B covers 4 m. While A covers 1m, B covers 4/3 m. While A covers 360 m, B covers (4/3* 360)m =480 m. Here time is same in case of speed.we count different distance in same time. |

Rajesh said: (Feb 7, 2013) | |

Can be solved by simple calculation. A covers 360m (ie) 500-140. Ratio of speeds of A:B = 3:4. Let us consider A covers 3m/sec & B covers 4m/sec. Time taken by A to cover 360m=(360/3)=120seconds. So,Distance covered by B in 120s =120*4=480m. Therefore,A wins by 20 metres which is (500-480). |

Srinu said: (Feb 8, 2015) | |

Time = dis\speed. T = 360\3 = 120sec. Now dis = sxT = 4x120 = 480m. So 500-480 = 20m. This is the answer. |

Newstein Faraday . said: (Jul 1, 2015) | |

A has to travel 360 meters therefore Time =distance/ speed. So 360/3 = 120 seconds. The same 120 seconds b has to travel so distance = speed x time = 4 x 120 = 480. The remaining distance that b has to travel is 500-480 = 20. |

Damini.Arora said: (Aug 25, 2015) | |

Here, because A has a start of 140, he has already covered 140 m when B starts. So when A covers rest of 360, B covers 480. Hence B loses race by 20 m. |

Ash said: (Jan 19, 2016) | |

Speed is directly proportional to distance. 3/4 = (500-140)/(500-x). 3/4 = 360/(500-x). Hence x = 20. |

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