Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 3)
3.
In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 140 m. Then, A wins by:
Answer: Option
Explanation:
To reach the winning post A will have to cover a distance of (500 - 140)m, i.e., 360 m.
While A covers 3 m, B covers 4 m.
| While A covers 360 m, B covers |  |
4 | x 360 |  m |
= 480 m. |
| 3 |
Thus, when A reaches the winning post, B covers 480 m and therefore remains 20 m behind.
A wins by 20 m.
Discussion:
14 comments Page 2 of 2.
Malli said:
1 decade ago
Hai, my dout is same that of vamsi.
Why we had taken 4/3 in problem?
Why we had taken 4/3 in problem?
Vamsi said:
1 decade ago
I didn't understand how it can be 4/3. ?
Sudheer said:
1 decade ago
Hi kriti here speed and distance are directly proportinal. If his speed is 10km/hr he cover 10km distance. If speed is 20km/hr he can cover 20 km distance. Thus speed and distance are directly proportinal. So here distance ratios also become3:4. But the time ratio will become4:3 because time and speed are inversly proportinal.
Kriti said:
1 decade ago
Hi, when 3:4 is the ratio of speeds how can we use it
as 3m and 4m for A and B resp.?
as 3m and 4m for A and B resp.?
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