Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - Data Sufficiency 2 (Q.No. 1)
Directions to Solve
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
- Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
- Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
- Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
- Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
- Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
1.
A man mixes two types of rice (X and Y) and sells the mixture at the rate of Rs. 17 per kg. Find his profit percentage. | |
I. | The rate of X is Rs. 20 per kg. |
II. | The rate of Y is Rs. 13 per kg. |
Answer: Option
Explanation:
The ratio, in which X and Y are mixed, is not given.
So, both I and II together cannot give the answer.
Correct answer is (D).
Discussion:
32 comments Page 2 of 4.
Kiran sinha said:
9 years ago
x 20/-
Y 13/-
Cp = 20+13 = 33.
Sp = 17x2 = 34.
Profit = (1/33)x100.
Option E.
Y 13/-
Cp = 20+13 = 33.
Sp = 17x2 = 34.
Profit = (1/33)x100.
Option E.
(1)
Manoj said:
9 years ago
Here the quantity of rice x and y are not given so data is insufficient.
Mounika said:
10 years ago
Ratio of mixture = 4:3.
Let us consider he mixes 4 kg of type one mix and 3 kg of type 2.
His cost price = (4*20) + (3*13) = 119.
Selling price = 7*17 = 119.
No profit no loss.
Let us consider he mixes 4 kg of type one mix and 3 kg of type 2.
His cost price = (4*20) + (3*13) = 119.
Selling price = 7*17 = 119.
No profit no loss.
Vibha said:
10 years ago
Option D is correct.
We can calculate the ratio in which both X and Y are mixed using mixtures n alligation but to calculate profit we need the total quantity of mixture, which is not given.
We can calculate the ratio in which both X and Y are mixed using mixtures n alligation but to calculate profit we need the total quantity of mixture, which is not given.
Pratima said:
10 years ago
"General Thinking" answer D is correct. Because the quantity is not mentioned. Suppose the shopkeeper mixes only some amount of X on Y or else only some amount of Y on X. It depends on the shopkeeper.
Ravinesh kumar said:
10 years ago
Average of (x+y) = 17/kg (for sell).
But x = 20/kg.
y = 13/kg.
Here, average of (x+y) = (20+13)/2 = 16.5/kg (cost price).
Profit percentage = (17-16.5)/16.5*100 = 3%.
But x = 20/kg.
y = 13/kg.
Here, average of (x+y) = (20+13)/2 = 16.5/kg (cost price).
Profit percentage = (17-16.5)/16.5*100 = 3%.
Bhupendra Gupta said:
10 years ago
We have to calculate profit per.
So it requires cost price ===> given but not clear that in what ratio we mixed them. So we have not cost price, and selling price is 17/kg but cost price is not clarify. So and D is correct.
So it requires cost price ===> given but not clear that in what ratio we mixed them. So we have not cost price, and selling price is 17/kg but cost price is not clarify. So and D is correct.
Vivek said:
10 years ago
We need both A and B to find profit. So option E is right.
Sparsh Chandra said:
1 decade ago
Option E will be correct only if both the type of rice are mixed in same ratio. So answer 100/33% = 3.33% as solved by AMIT is correct but here it is not defined whether the mixture of them was done in same ratio or different.
So D will be correct. So the question is not exactly defined.
So D will be correct. So the question is not exactly defined.
Harshad said:
1 decade ago
No option E is incorrect. Right answer is D.
Because the ratio of mixing is important. We just can't assume he mixed same quantity of both rice (x and y).
What if he mixed 1 kg of x and 9999 kg of y.
So total 10,000 kg and cost will be (20+9999*13) = 1,30,007.
And sp for 10000 kg =17*10000 = 1,70,000.
Profit = 39993 and % will be 3.07.
And what if we consider the other way round. Like what if he mixed 1 kg of y and 9999 kg of x.
That time he will be in loss.
Because the ratio of mixing is important. We just can't assume he mixed same quantity of both rice (x and y).
What if he mixed 1 kg of x and 9999 kg of y.
So total 10,000 kg and cost will be (20+9999*13) = 1,30,007.
And sp for 10000 kg =17*10000 = 1,70,000.
Profit = 39993 and % will be 3.07.
And what if we consider the other way round. Like what if he mixed 1 kg of y and 9999 kg of x.
That time he will be in loss.
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