Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 11)
11.
On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is:
Answer: Option
Explanation:
(C.P. of 17 balls) - (S.P. of 17 balls) = (C.P. of 5 balls)
C.P. of 12 balls = S.P. of 17 balls = Rs.720.
| C.P. of 1 ball = Rs. |
 |
720 |  |
= Rs. 60. |
| 12 |
Discussion:
91 comments Page 2 of 10.
Manasa said:
1 decade ago
Consider cp of 1 ball =x
for 17 balls=17x;
loss=cp-sp(here 17balls cost price-17balls selling price)
i.e 17x-720;
for 5 balls cp is 5x;
in the question he give 17 balls loss=cp of 5 balls
i.e 17x-720=5x;
17x-5x=720;
12x=720;
x=720/12;
x=60.
for 17 balls=17x;
loss=cp-sp(here 17balls cost price-17balls selling price)
i.e 17x-720;
for 5 balls cp is 5x;
in the question he give 17 balls loss=cp of 5 balls
i.e 17x-720=5x;
17x-5x=720;
12x=720;
x=720/12;
x=60.
(13)
Ankit Ardeshana said:
10 years ago
Loss for 17 balls = cp of 5 balls.
=> cp of 17 balls - sp of 17 balls = cp of 5 balls.
=> (cp of 17 balls - cp of 5 balls) = sp of 17 balls.
But sp of 17 balls = 720.
=>cp of 12 balls = 720.
=>cp of 1 ball = 720/12 = 60.
=> cp of 17 balls - sp of 17 balls = cp of 5 balls.
=> (cp of 17 balls - cp of 5 balls) = sp of 17 balls.
But sp of 17 balls = 720.
=>cp of 12 balls = 720.
=>cp of 1 ball = 720/12 = 60.
Jitendra said:
1 decade ago
Its given.
(CP*17) - (SP*17) = (CP*5) its loss.
Selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls.
Now consider 1 ball's cost is "x".
(x*17) - (720) = (x*5).
17x-720=5x.
17x-5x=720.
12x=720.
x=720/12.
X=60.
(CP*17) - (SP*17) = (CP*5) its loss.
Selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls.
Now consider 1 ball's cost is "x".
(x*17) - (720) = (x*5).
17x-720=5x.
17x-5x=720.
12x=720.
x=720/12.
X=60.
Hema said:
1 decade ago
Let cost price of 1 ball=x
then cost price of 17 balls=17x
loss is equal to 5 balls cost price(given in problem)=5x
selling price=c.p-loss=17x-5x=12x
but original selling price=720
.
. . 12x=720
x=60
c.p of 1 ball=60
then cost price of 17 balls=17x
loss is equal to 5 balls cost price(given in problem)=5x
selling price=c.p-loss=17x-5x=12x
but original selling price=720
.
. . 12x=720
x=60
c.p of 1 ball=60
Uma said:
9 years ago
C.P of 17 balls = x.
Loss = C.P of 5 balls.
1 ball C.P is x/17.
5 balls C.P is 5x/17.
Loss = 5x/17.
17 balls C.P = 17 balls S.P+Loss.
x = 720+5x/17.
12x = 720*17.
x = 60*17.
Then each ball price is (x/17) = ((60*17)/17) = 60.
Loss = C.P of 5 balls.
1 ball C.P is x/17.
5 balls C.P is 5x/17.
Loss = 5x/17.
17 balls C.P = 17 balls S.P+Loss.
x = 720+5x/17.
12x = 720*17.
x = 60*17.
Then each ball price is (x/17) = ((60*17)/17) = 60.
Sanket said:
8 years ago
Let cp for 1 ball = x rs.
sp for 1 ball =720/17 rs.
***please note***(for 17 balls, loss = 5x therefore loss behind 1 ball = 5x/17)
Now, loss over 1 ball = c.p. over 1 ball - sp over 1 ball.
5x/17 = x - 720/17,
x = 60.
sp for 1 ball =720/17 rs.
***please note***(for 17 balls, loss = 5x therefore loss behind 1 ball = 5x/17)
Now, loss over 1 ball = c.p. over 1 ball - sp over 1 ball.
5x/17 = x - 720/17,
x = 60.
Avnish said:
1 decade ago
Let us assume C. P of 5 balls be 'c'.
Then C.P of 17 balls 17c/5.
NOW, LOSS=C.P of 5 balls.
i.e., (C.P of 17 balls) - (S.P of 17 balls) = C.P of 5 balls.
(17c/5) - (720) = c.
(or) c = 300.
Any queries are welcomed ?
Then C.P of 17 balls 17c/5.
NOW, LOSS=C.P of 5 balls.
i.e., (C.P of 17 balls) - (S.P of 17 balls) = C.P of 5 balls.
(17c/5) - (720) = c.
(or) c = 300.
Any queries are welcomed ?
Tina said:
1 decade ago
In the question, it is given the that on selling 17 balls at rs 720, the loss is equal to cost prize of 5 balls, but why have we subtracted it from cost prize of 17 balls when it is no where mentioned in the question ?
Avijit said:
10 years ago
Let C.P is x then.
According to question condition of loss.
(C.P of 17 balls) - (S.P of 17 balls) = (C.P of 5 balls).
=> (17*x) - 720 = (5*x).
=> 17x - 5x =720.
=> 12x = 720.
x = 720/12.
=> x = 60.
According to question condition of loss.
(C.P of 17 balls) - (S.P of 17 balls) = (C.P of 5 balls).
=> (17*x) - 720 = (5*x).
=> 17x - 5x =720.
=> 12x = 720.
x = 720/12.
=> x = 60.
Baskar said:
1 decade ago
Loss = C.P-S.P.
From given: S.P of 17 balls = 720 R.S.
Loss = C.P of 5 balls.
From 1st equation.
C.P of 5 balls = C.P of 17 balls - S.P of 17 balls.
Let C.P of 1 ball = x.
5x = 17x-720.
12x = 720.
x = 60.
From given: S.P of 17 balls = 720 R.S.
Loss = C.P of 5 balls.
From 1st equation.
C.P of 5 balls = C.P of 17 balls - S.P of 17 balls.
Let C.P of 1 ball = x.
5x = 17x-720.
12x = 720.
x = 60.
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