Aptitude - Profit and Loss - Discussion

Why it is 2(y-x) instead of 2y as selling price doubles?

Let S.P - x, C.P-Y.

Given,
2 S.P = 3 P.
2 x = 3( X - Y),
From here find C.P i.e,
Y = X/3.

Now find profit P=X-Y.
=X - X/3. (Bcz, Y=X/3),
= X/3.

Now use P% formula.

P% = P/C.P * 100.
= X/3/X/3 *100,
= 100%.

Observe that there are two cases given in this question.

We know that for solving two variables we need at least two relations.

Here,
Case 1.
CP is x.
SP is y.
So, the gain is y-x.

Case 2.
CP is x
SP is 2y (sp is doubled)
So, the gain is 2y-x (according to question this quantity is 3 times the gain in Case 1).

On solving case 1 and 2 according to the question.
3(y-x)=2y-x.
Or y=2x.

Now, it is observable that they are asking the gain% of case 1 (case 2 is only given for finding a relation between x and y).

So the gain per cent (of case 1) will be;
Gain% = (gain/cp)*100.
= {(y-x)/x}*100,
= {(2x-x)/x}*100.

Gain% = (x/x)*100.
Gain% = 100%.

I hope you notice that the question asks for gain% for case 1.

Thank you

Let,

The
Cost Price = x.
Selling Price = 2x.

The formula is; (SP-CP)/CP * 100.

(2x-x)/x * 100 = 100% (Ans).

@Bhagath.

Gain%=(Gain*100)/C.P.

65%= (x*100)/2(65%).
65% = (x*100)/(130%),
65%*130% = (x*100),
X = 8.45%.

@ Sangeetha k.

The formula for profit % is (Profit/CP)/100.

If the selling price is tripled and cost price is doubled profit becomes 65%. What is the present profit%?

Can anyone answer this?

Let the C.P be Rs.100 and S.P be Rs.x, Then

The profit is (x-100)
Now the S.P is doubled, then the new S.P is 2x,
New profit is (2x-100),
Now as per the given condition;
=> 3(x-100) = 2 x-100,
By solving, we get;
x = 200.

Then the Profit percent = (200-100)/100 = 100.
Hence the profit percentage is 100%.

Let c.p=X,s.p=2X.

The gain=2X-X=X (s.p-c.p).
And gain%=X/X*100 (gain*100)/c.p.

Well said, Thanks. @Sarfaraz Khan.