Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) 
y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
 Profit % = |
 |
x | x 100 |  % = 100% |
| x |
Video Explanation: https://youtu.be/dPzF10mGsWE
Discussion:
306 comments Page 7 of 31.
Siddu 324 said:
6 years ago
Assume CP = x then SP increase double of CP.
Then SP = 2x.
Formula for gain% = {(gain) X 100/CP}.
Then gain%= (x/x) X 100.
Then finally gain% = 100.
Then SP = 2x.
Formula for gain% = {(gain) X 100/CP}.
Then gain%= (x/x) X 100.
Then finally gain% = 100.
Sahil Mayekar said:
6 years ago
P : Profit.
X : Price.
R : RATE.
INITIALLY,
X + P = X + XR/100.
P = XR/100 -----------(1).
BUT WHEN WE DOUBLES THE PRICE,
X + 3P = 2X + 2XR.
BECAUSE WE WANT TO FIND R,
3P = X + 2XR/100.
P = (X + (2XR/100))/3.
Put above P in Equation (1).
(X + (2XR/100))/3 = XR/100.
X + 2XR/100 = 3XR/100.
X = XR/100.
100 = R.
R = 100%.
X : Price.
R : RATE.
INITIALLY,
X + P = X + XR/100.
P = XR/100 -----------(1).
BUT WHEN WE DOUBLES THE PRICE,
X + 3P = 2X + 2XR.
BECAUSE WE WANT TO FIND R,
3P = X + 2XR/100.
P = (X + (2XR/100))/3.
Put above P in Equation (1).
(X + (2XR/100))/3 = XR/100.
X + 2XR/100 = 3XR/100.
X = XR/100.
100 = R.
R = 100%.
Anomii said:
6 years ago
Why did you take 3(y-x) = (2y-x)?
Can someone please explain?
Can someone please explain?
Devamanen said:
6 years ago
Guys,
It's simple.
For example
Sp =rs100,
Sp =rs110.
Now, Sp is doubled.
(ie) :sp=2(110) rs=>220 but remember cp remains the same.
Then, we know.
1) profit=sp-cp
2) profit %= (sp-cp/cp)100.
From the question;
If Sp is doubled the profit triple so with this we build the equation.
2sp-cp = 3(profit).
(ie)
2sp-cp=3(sp-cp).
We get
Sp=2cp ---> (1)
To find profit %
(Sp-cp/cp) 100.
Sub 1 in the formula above;
(2cp-cp/cp)100.
So, finally, we get 100%.
It's simple.
For example
Sp =rs100,
Sp =rs110.
Now, Sp is doubled.
(ie) :sp=2(110) rs=>220 but remember cp remains the same.
Then, we know.
1) profit=sp-cp
2) profit %= (sp-cp/cp)100.
From the question;
If Sp is doubled the profit triple so with this we build the equation.
2sp-cp = 3(profit).
(ie)
2sp-cp=3(sp-cp).
We get
Sp=2cp ---> (1)
To find profit %
(Sp-cp/cp) 100.
Sub 1 in the formula above;
(2cp-cp/cp)100.
So, finally, we get 100%.
Vagisha said:
6 years ago
FROM %P FORMULA.
WE KNOW;
SP = ((100+%P) /100 ) *CP
so 100 and CP being constant we have the relation
SP is directly proportional to 100+%P
thus;
SP1/SP2 = (100+%P1) / (100+%P2).
Given SP=2SP.
And P = 3P.
THUS
SP / 2SP = (100+P)/(100+3P).
On simplifying;
100+3P = 200+2P,
GIVING
P = 100.
WE KNOW;
SP = ((100+%P) /100 ) *CP
so 100 and CP being constant we have the relation
SP is directly proportional to 100+%P
thus;
SP1/SP2 = (100+%P1) / (100+%P2).
Given SP=2SP.
And P = 3P.
THUS
SP / 2SP = (100+P)/(100+3P).
On simplifying;
100+3P = 200+2P,
GIVING
P = 100.
Vijay Prasanth A said:
6 years ago
Here for profit % we need to take profit as 2y-x or 3(y-x) but you take it as y-x.
I think we assume profit has tripled.
I think we assume profit has tripled.
Md. Arif Hossain said:
6 years ago
Let,
Sp = 30.
Profit = 10.
Now if sp becomes double the new sp would be 30*2= 60 and if profit triple then new profit would be = 10*3= 30.
So, new cp = 60-30=30.
So, profit percentage would be = new profit/new cp *100.
= 30/30*100 =100%.
Sp = 30.
Profit = 10.
Now if sp becomes double the new sp would be 30*2= 60 and if profit triple then new profit would be = 10*3= 30.
So, new cp = 60-30=30.
So, profit percentage would be = new profit/new cp *100.
= 30/30*100 =100%.
Shiva rana magar said:
6 years ago
Let c.p. be x and s.p. be y.
We know that;
profit =s.p.-c.p.
=y-x------------> equation 1.
According to question;
Selling price is doubled then the profit triples so,
3(y-x)=2y-x -------------> (selling price is doubled and profit is tripled from equation 1)
or, 3y-3x=2y-x.
or, y=2x.
Now, keeping the value of y in equation 1 we get;
profit =2x-x.
=x,
Profit%= profit/c.p.
= x/x*100%,
=100%.
We know that;
profit =s.p.-c.p.
=y-x------------> equation 1.
According to question;
Selling price is doubled then the profit triples so,
3(y-x)=2y-x -------------> (selling price is doubled and profit is tripled from equation 1)
or, 3y-3x=2y-x.
or, y=2x.
Now, keeping the value of y in equation 1 we get;
profit =2x-x.
=x,
Profit%= profit/c.p.
= x/x*100%,
=100%.
Tejas dhavalikar said:
6 years ago
Simply, it is solved by;.
20 articles and 25 % we have taken 125 % so added 100.
20*100/125=16.
20 articles and 25 % we have taken 125 % so added 100.
20*100/125=16.
Ranjita said:
6 years ago
Why we not take as 3z = 2y-x?
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