Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) 
y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
 Profit % = |
 |
x | x 100 |  % = 100% |
| x |
Video Explanation: https://youtu.be/dPzF10mGsWE
Discussion:
303 comments Page 6 of 31.
Aviral Tiwari said:
5 years ago
I can't understand that it is saying if the selling price is doubled then the profit triples which means 2y=3 (y-x). Please suggest to me.
Ruhi said:
5 years ago
X is cp and y is sp.
Here we are equating profits,
Profit means sp-cp,
Triple the profit means 3(y-x) (y-x) means profit,
Double the sp. Here we know y is sp in terms of profit,
2y-x,
So 3(y-x)=2y-x.
Solving we get y=2x means 2times of cp is one time of sp. So one time of cp is profit.
Profit%= profit/cp*100.
So profit%= one time of cp is profit I.e x and cp x.
Hence profit%= x/x*100=100%.
Here we are equating profits,
Profit means sp-cp,
Triple the profit means 3(y-x) (y-x) means profit,
Double the sp. Here we know y is sp in terms of profit,
2y-x,
So 3(y-x)=2y-x.
Solving we get y=2x means 2times of cp is one time of sp. So one time of cp is profit.
Profit%= profit/cp*100.
So profit%= one time of cp is profit I.e x and cp x.
Hence profit%= x/x*100=100%.
MARISELVAM M said:
5 years ago
I can't understand the second step. Can you please explain it?
PGN said:
6 years ago
P=s.p-c.p.
According to condition,
3P= 2(s.p)-c.p,
Solve the equations simultaneously.
We get.
s.p=2P.
c.p=P.
Now
P%=(s.p-c.p/cp) * 100.
Put values, we get;
P%=100.
According to condition,
3P= 2(s.p)-c.p,
Solve the equations simultaneously.
We get.
s.p=2P.
c.p=P.
Now
P%=(s.p-c.p/cp) * 100.
Put values, we get;
P%=100.
Swaathi said:
6 years ago
Please read the question carefully,
S.P. is doubled.
Profit triples.
Let C.P. = 10, S.P. =20, Profit =30.
Profit%= (S.P. - C.P. ) / (C.P. ) *100.
= (20-10) / (10) *100.
=10/10*100.
=100%.
SOLVED.
S.P. is doubled.
Profit triples.
Let C.P. = 10, S.P. =20, Profit =30.
Profit%= (S.P. - C.P. ) / (C.P. ) *100.
= (20-10) / (10) *100.
=10/10*100.
=100%.
SOLVED.
(1)
V.krishna (v.k) said:
6 years ago
Given S.P is doubled,
Let us think S.P = 100 and profit = 50.
Now S.P is doubled = 200.
C.P = 50 as C.P = S.P-Profit.
Profit = S.P - C.P.
=200 - 50.
= 150.
Profit is tripled as (50)(3) = 150.
Let us think S.P = 100 and profit = 50.
Now S.P is doubled = 200.
C.P = 50 as C.P = S.P-Profit.
Profit = S.P - C.P.
=200 - 50.
= 150.
Profit is tripled as (50)(3) = 150.
Gurpreet.singh said:
6 years ago
Let's suppose C.P=100 then If I double it S.P would become 200.
Profit would be 200-100=100, it's not tripled, the question is bit confusing.
Profit would be 200-100=100, it's not tripled, the question is bit confusing.
Siddu 324 said:
6 years ago
Assume CP = x then SP increase double of CP.
Then SP = 2x.
Formula for gain% = {(gain) X 100/CP}.
Then gain%= (x/x) X 100.
Then finally gain% = 100.
Then SP = 2x.
Formula for gain% = {(gain) X 100/CP}.
Then gain%= (x/x) X 100.
Then finally gain% = 100.
Sahil Mayekar said:
6 years ago
P : Profit.
X : Price.
R : RATE.
INITIALLY,
X + P = X + XR/100.
P = XR/100 -----------(1).
BUT WHEN WE DOUBLES THE PRICE,
X + 3P = 2X + 2XR.
BECAUSE WE WANT TO FIND R,
3P = X + 2XR/100.
P = (X + (2XR/100))/3.
Put above P in Equation (1).
(X + (2XR/100))/3 = XR/100.
X + 2XR/100 = 3XR/100.
X = XR/100.
100 = R.
R = 100%.
X : Price.
R : RATE.
INITIALLY,
X + P = X + XR/100.
P = XR/100 -----------(1).
BUT WHEN WE DOUBLES THE PRICE,
X + 3P = 2X + 2XR.
BECAUSE WE WANT TO FIND R,
3P = X + 2XR/100.
P = (X + (2XR/100))/3.
Put above P in Equation (1).
(X + (2XR/100))/3 = XR/100.
X + 2XR/100 = 3XR/100.
X = XR/100.
100 = R.
R = 100%.
Anomii said:
6 years ago
Why did you take 3(y-x) = (2y-x)?
Can someone please explain?
Can someone please explain?
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