Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) 
y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
 Profit % = |
 |
x | x 100 |  % = 100% |
| x |
Video Explanation: https://youtu.be/dPzF10mGsWE
Discussion:
304 comments Page 5 of 31.
Ramya.k said:
10 years ago
Let profit be 'p', S.P be 'y' and C.P be 'x'.
Now we know that profit = S.P-C.P.
i.e, p = y-x ----- (1) (say);
Now according to problem 3p = 2y-x--- (2) (say).
Now substitute (1) in (2).
Then, 3(y-x) = 2y-x;
3y-3x = 2y-x;
3y-2y = 3x-x;
y = 2x---- (3) (say);
Now put (3) in (1);
Then p = 2x-x;
Now p% = ((2x-x)/x)*100;
P% = (x/x)*100;
P% = 100;
Now we know that profit = S.P-C.P.
i.e, p = y-x ----- (1) (say);
Now according to problem 3p = 2y-x--- (2) (say).
Now substitute (1) in (2).
Then, 3(y-x) = 2y-x;
3y-3x = 2y-x;
3y-2y = 3x-x;
y = 2x---- (3) (say);
Now put (3) in (1);
Then p = 2x-x;
Now p% = ((2x-x)/x)*100;
P% = (x/x)*100;
P% = 100;
Niharul Islam said:
10 years ago
We know, Profit (P) = Selling Price (y) - Costing Price (x)....(1).
Given, 3p = 2y - x.
=> p = (2y-X)/3.....(2).
From equation 1 &2 we get,
y - x = (2y-x)/3.
=> 3y - 3x = 2y-x.
=> 3y - 2y = -x + 3x.
=> y = 2x.
We know Profit Equation,
Profit = (y-x)/x.
= (2x - x)/x.
= x/x.
= 1*100% = 100%.
This is the 100% answer of this math.
Given, 3p = 2y - x.
=> p = (2y-X)/3.....(2).
From equation 1 &2 we get,
y - x = (2y-x)/3.
=> 3y - 3x = 2y-x.
=> 3y - 2y = -x + 3x.
=> y = 2x.
We know Profit Equation,
Profit = (y-x)/x.
= (2x - x)/x.
= x/x.
= 1*100% = 100%.
This is the 100% answer of this math.
Gaurav said:
1 decade ago
@Pooja but just for clarification.
If you calculate the profit it will not be tripled !
They should add one more option as 300%
If you buy a pencil for 5 rs sell it for 10rs you have a profit of 5rs that's 100% profit !
CP = 5rs.
SP(doubled) = 20rs.
Profit = 20-5 = 15rs.
Profit is thrice the profit it was before 5x3.
Then profit becomes 300%
If you calculate the profit it will not be tripled !
They should add one more option as 300%
If you buy a pencil for 5 rs sell it for 10rs you have a profit of 5rs that's 100% profit !
CP = 5rs.
SP(doubled) = 20rs.
Profit = 20-5 = 15rs.
Profit is thrice the profit it was before 5x3.
Then profit becomes 300%
Reshma krishnan said:
7 years ago
Cp=x and sp=y.
Profit =sp-cp,
Profit=3(y-x)________(1)[triple the profit]
Profit=2y-x__________(2)[selling price double]
Equate (1) &(2)
3(y-x)=2y-x,
3y-3x=2y-x,
3y-2y=-x+3x.
Y=2x [ selling price is 2x],
Profit =sp-cp,
=y-x,
=2x-x
=x.
Profit %= profit÷cp *100,
=x÷x *100,
=100%.
Profit =sp-cp,
Profit=3(y-x)________(1)[triple the profit]
Profit=2y-x__________(2)[selling price double]
Equate (1) &(2)
3(y-x)=2y-x,
3y-3x=2y-x,
3y-2y=-x+3x.
Y=2x [ selling price is 2x],
Profit =sp-cp,
=y-x,
=2x-x
=x.
Profit %= profit÷cp *100,
=x÷x *100,
=100%.
Chintu jareda said:
8 years ago
Since c.p. remain unchanged .let it be Rs. x.
Let s.p. = Rs y.
Profit= y-x.
If s.p. is doubled i.e it becomes 2y then profit = 2y -x.
As given that this profit is trippled.
i.e. 3*(y-x) = 2y-x.
From which we get (y/x)=2.
%profit = (profit/c.p) * 100.
= (s.p./c.p.-1) * 100,
= (y/x-1) * 100,
= (2-1) * 100,
= 100% Ans.
Let s.p. = Rs y.
Profit= y-x.
If s.p. is doubled i.e it becomes 2y then profit = 2y -x.
As given that this profit is trippled.
i.e. 3*(y-x) = 2y-x.
From which we get (y/x)=2.
%profit = (profit/c.p) * 100.
= (s.p./c.p.-1) * 100,
= (y/x-1) * 100,
= (2-1) * 100,
= 100% Ans.
Shekhar adhikari said:
9 years ago
Let CP =x and SP = y.
According to the question 3(y - x) = 2y - x.
Here in question this equation 'is given as condition only.S.P is already fixed.
This condition connects between SP and Cp from this condition we get the relation betweenSP and Cp as y = 2x .
Then we should take profit => y - x = 2x - x = x.
Thus profit % = x/x *100 = 100%.
According to the question 3(y - x) = 2y - x.
Here in question this equation 'is given as condition only.S.P is already fixed.
This condition connects between SP and Cp from this condition we get the relation betweenSP and Cp as y = 2x .
Then we should take profit => y - x = 2x - x = x.
Thus profit % = x/x *100 = 100%.
Saurabh said:
1 decade ago
As u all know profit= selling_price - cost_price-----eqn1
Now from give data i found new eqn---2:
3*profit=2*selling_price - cost_price----eqn2
So from first n second i found cost_price=profit
As u know %profit= profit*100/cost_price----eqn3
So put the value of cost_price in eqn--3 it means that %profit=100
Hope it is easy to understand.
Now from give data i found new eqn---2:
3*profit=2*selling_price - cost_price----eqn2
So from first n second i found cost_price=profit
As u know %profit= profit*100/cost_price----eqn3
So put the value of cost_price in eqn--3 it means that %profit=100
Hope it is easy to understand.
Shubhi said:
7 years ago
Its so easy to solve the problem:
Firstly,we assume the C.P be x Rs. ( i.e c.p = x Rs )
That mean S.P is doubled of c.p i.e 2x Rs. ( i.e s.p = 2x Rs )
Then profit = s.p - c.p.
= 2x -x.
profit = x rs.
Then, profit % = (profit * 100 /c.p).
= (x *100 / x),
profit% = 100 rs.
Firstly,we assume the C.P be x Rs. ( i.e c.p = x Rs )
That mean S.P is doubled of c.p i.e 2x Rs. ( i.e s.p = 2x Rs )
Then profit = s.p - c.p.
= 2x -x.
profit = x rs.
Then, profit % = (profit * 100 /c.p).
= (x *100 / x),
profit% = 100 rs.
Hamzah Bhatti said:
1 decade ago
Let Cost Price Be X AND Selling Price be Y And Profit for this is Z, THEN BY given Condition
((y-x)/x)*100=Z -------------- (1)
Similarly By Given Condition
((2y-x)/x)*100 =3Z Or Z = ((2Y-X)/3X)*100 -------- (2)
Both eqn 1 and 2 are equal equating these two eqn gives
3(y-x) =2y-x
y=2x
Put this value in eqn 1 and get z = 100.
((y-x)/x)*100=Z -------------- (1)
Similarly By Given Condition
((2y-x)/x)*100 =3Z Or Z = ((2Y-X)/3X)*100 -------- (2)
Both eqn 1 and 2 are equal equating these two eqn gives
3(y-x) =2y-x
y=2x
Put this value in eqn 1 and get z = 100.
Sharath said:
8 years ago
Profit = sp-cp......1.
New sp = 2sp(given)
New profit = 3profit(given)
New profit =new sp - cp.
i.e 3profit= 2sp-cp.......2
2 divided by 1.
3=(2sp-cp)/(sp - cp).
After simplification we get sp= 2cp.
Substitute this in profit equation.
Profit = 2cp - cp.
=> profit = cp.
%profit= (profit/cp) * 100.
=>(cp/cp) * 100.
Hence 100%.
New sp = 2sp(given)
New profit = 3profit(given)
New profit =new sp - cp.
i.e 3profit= 2sp-cp.......2
2 divided by 1.
3=(2sp-cp)/(sp - cp).
After simplification we get sp= 2cp.
Substitute this in profit equation.
Profit = 2cp - cp.
=> profit = cp.
%profit= (profit/cp) * 100.
=>(cp/cp) * 100.
Hence 100%.
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