Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
![]() |
![]() |
x | x 100 | ![]() |
x |
Video Explanation: https://youtu.be/dPzF10mGsWE
Discussion:
304 comments Page 4 of 31.
Neeraj said:
4 years ago
I have a doubt, is the question asking to calculate profit before doubling the SP or after?
Let us assume SP = Rs 6, CP = Rs 3, Profit = Rs 3.
As per question new SP = Rs 12, CP will remain same Rs 3 , Profit = Rs 9 ( triple of previous).
in 1st case P% = P/CPx100 = 3/3 x100 = 100%.
in 2nd case P% = 9/3 x100 = 300%.
Please confirm what is specified by the question? Profit in 1st case or 2nd case. Please explain me.
Let us assume SP = Rs 6, CP = Rs 3, Profit = Rs 3.
As per question new SP = Rs 12, CP will remain same Rs 3 , Profit = Rs 9 ( triple of previous).
in 1st case P% = P/CPx100 = 3/3 x100 = 100%.
in 2nd case P% = 9/3 x100 = 300%.
Please confirm what is specified by the question? Profit in 1st case or 2nd case. Please explain me.
(4)
Neeraj said:
4 years ago
I have a doubt, is the question asking to calculate profit before doubling the SP or after?
Let us assume SP = Rs 6, CP = Rs 3, Profit = Rs 3.
As per question new SP = Rs 12, CP will remain same Rs 3 , Profit = Rs 9 ( triple of previous).
in 1st case P% = P/CPx100 = 3/3 x100 = 100%.
in 2nd case P% = 9/3 x100 = 300%.
Please confirm what is specified by the question? Profit in 1st case or 2nd case. Please explain me.
Let us assume SP = Rs 6, CP = Rs 3, Profit = Rs 3.
As per question new SP = Rs 12, CP will remain same Rs 3 , Profit = Rs 9 ( triple of previous).
in 1st case P% = P/CPx100 = 3/3 x100 = 100%.
in 2nd case P% = 9/3 x100 = 300%.
Please confirm what is specified by the question? Profit in 1st case or 2nd case. Please explain me.
(1)
Waseem Mir said:
7 years ago
We know that profit% = (gainx100÷CP)......"i"
SP-CP=profit......."ii"
Also, 2SP-CP=3profit......."iii"
Therefore by subtracting "ii" from"iii"
We get SP=2profit.
Again we use SP-CP=profit.
Put value SP=2profit in it....."iiii"
We get CP=profit.
Now let CP be 100.
So profit/gain =100.
Using equation %profit=(gain*100÷CP).
We get profit% =100.
SP-CP=profit......."ii"
Also, 2SP-CP=3profit......."iii"
Therefore by subtracting "ii" from"iii"
We get SP=2profit.
Again we use SP-CP=profit.
Put value SP=2profit in it....."iiii"
We get CP=profit.
Now let CP be 100.
So profit/gain =100.
Using equation %profit=(gain*100÷CP).
We get profit% =100.
Mayank sharma said:
10 years ago
Very simple and easy approach.
Let SP =10.
And profit be X. So CP = 10-X equation 1.
Now SP doubles means it became 20. And profit triples means it become 3X.
So now CP = 20-3X equation 2.
Now equate equation 1 and 2.
10-X = 20-3X.
X = 5 means it is profit.
Now with X we can calculation CP by any one equation.
Then profit percent = P*100/CP.
5/5*100 = 100%.
It is the easiest way to solve.
Let SP =10.
And profit be X. So CP = 10-X equation 1.
Now SP doubles means it became 20. And profit triples means it become 3X.
So now CP = 20-3X equation 2.
Now equate equation 1 and 2.
10-X = 20-3X.
X = 5 means it is profit.
Now with X we can calculation CP by any one equation.
Then profit percent = P*100/CP.
5/5*100 = 100%.
It is the easiest way to solve.
Ruhi said:
5 years ago
X is cp and y is sp.
Here we are equating profits,
Profit means sp-cp,
Triple the profit means 3(y-x) (y-x) means profit,
Double the sp. Here we know y is sp in terms of profit,
2y-x,
So 3(y-x)=2y-x.
Solving we get y=2x means 2times of cp is one time of sp. So one time of cp is profit.
Profit%= profit/cp*100.
So profit%= one time of cp is profit I.e x and cp x.
Hence profit%= x/x*100=100%.
Here we are equating profits,
Profit means sp-cp,
Triple the profit means 3(y-x) (y-x) means profit,
Double the sp. Here we know y is sp in terms of profit,
2y-x,
So 3(y-x)=2y-x.
Solving we get y=2x means 2times of cp is one time of sp. So one time of cp is profit.
Profit%= profit/cp*100.
So profit%= one time of cp is profit I.e x and cp x.
Hence profit%= x/x*100=100%.
Tharun said:
8 years ago
Let the C.P. be x and the S.P be y.
So the profit is (y - x) ---------------------------- (1)
Now, the S.P. is doubled. So the new S.P. = 2y.
The new profit = (2y - x).
Given that when S.P. is doubled, profit increases 3 times
=> New profit = 3 * old profit,
=> (2y - x) = 3(y - x),
=> y = 2x.
So, the profit = (y - x) = (2x - x) = x.
% profit = (x * 100)% = 100%.
So the profit is (y - x) ---------------------------- (1)
Now, the S.P. is doubled. So the new S.P. = 2y.
The new profit = (2y - x).
Given that when S.P. is doubled, profit increases 3 times
=> New profit = 3 * old profit,
=> (2y - x) = 3(y - x),
=> y = 2x.
So, the profit = (y - x) = (2x - x) = x.
% profit = (x * 100)% = 100%.
Diforce Kumar Mehta said:
3 years ago
1st condition.
Let cp = x and sp=y
Profit = y-x.
2nd condition,
When sp is doubled,sp=2y.
Profit becomes triples, profit =3(y-x).
So,cp = sp - profit.
= 2y-3(y-x) = 3x - y.
As we know, cp at very condition will be the same.
3x-y = x.
2x = y.
Profit % = (profit/cp) * 100%,
= (y-x)/x * 100%,
= (2x-x)/x * 100%,
= 100%.
Let cp = x and sp=y
Profit = y-x.
2nd condition,
When sp is doubled,sp=2y.
Profit becomes triples, profit =3(y-x).
So,cp = sp - profit.
= 2y-3(y-x) = 3x - y.
As we know, cp at very condition will be the same.
3x-y = x.
2x = y.
Profit % = (profit/cp) * 100%,
= (y-x)/x * 100%,
= (2x-x)/x * 100%,
= 100%.
(30)
Madhavi said:
4 years ago
It's clearly mentioned in the question.
i) 2S.P - C.P = 3Profit
ii)Profit = S.P - C.P.
Now substitute ii in i, then you will get,
2S.P-C.P = 3(S.P-C.P).
After the simplification.
S.P = 2C.P.
* iii) (S.P/C.P)=2.
Now we have to find the profit%.
Profit%=((S.P-C.P)/C.P)*100 = {(S.P/C.P)-1}*100.
Substituting iii in above will give you (2-1)*100 = 100,
So the Profit %=100.
i) 2S.P - C.P = 3Profit
ii)Profit = S.P - C.P.
Now substitute ii in i, then you will get,
2S.P-C.P = 3(S.P-C.P).
After the simplification.
S.P = 2C.P.
* iii) (S.P/C.P)=2.
Now we have to find the profit%.
Profit%=((S.P-C.P)/C.P)*100 = {(S.P/C.P)-1}*100.
Substituting iii in above will give you (2-1)*100 = 100,
So the Profit %=100.
(1)
DEBLINA DUTTA said:
1 decade ago
Let, CP: 'X' and SP: 'Y' and profit : 'P'.
Then, P= (Y-X) / X ----------- (1).
Now, new SP= '2Y' and new profit : '3P'.
Then, 3P= (2Y-X) / X -------------- (2).
Put the value of 'P' from equation number (1).
So, (2Y-X) / X = (3Y-3X) / X.
Or, 2XY-X^2 = 3XY-3X^2.
Or, Y = 2X.
Put the value of 'Y' in eqn no. (1).
So, (2X-X) / X = P = 1*100 =100.
(ie) 100%.
Then, P= (Y-X) / X ----------- (1).
Now, new SP= '2Y' and new profit : '3P'.
Then, 3P= (2Y-X) / X -------------- (2).
Put the value of 'P' from equation number (1).
So, (2Y-X) / X = (3Y-3X) / X.
Or, 2XY-X^2 = 3XY-3X^2.
Or, Y = 2X.
Put the value of 'Y' in eqn no. (1).
So, (2X-X) / X = P = 1*100 =100.
(ie) 100%.
Abhinand k said:
7 years ago
We take selling price as -x and cost price- y we assume this! Then given sp is doubled so the profit will be s.p - c. P = 2X-Y.
Also, profit becomes tripled means 3* (x-y).
Therefore equatting 2x-y = 3(x-y) , we get x=2y or y=x/2! Now We know profit = (gain*100)/C P.
Gain is x-y we got y=2y substituting here we get gain= 2y-y=y therefore profit=y*100/y=100.
Also, profit becomes tripled means 3* (x-y).
Therefore equatting 2x-y = 3(x-y) , we get x=2y or y=x/2! Now We know profit = (gain*100)/C P.
Gain is x-y we got y=2y substituting here we get gain= 2y-y=y therefore profit=y*100/y=100.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers