Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) 
y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
 Profit % = |
 |
x | x 100 |  % = 100% |
| x |
Video Explanation: https://youtu.be/dPzF10mGsWE
Discussion:
308 comments Page 18 of 31.
Rajiya said:
10 years ago
P = S.P - C.P.
Profit triples and S.P doubles.
3P = 2S.P - C.P.
3(S.P - C.P) = 2S.P - C.P.
So, S.P = 2C.P.
S.P/C.P = 2/1.
P = 1 / 1*100.
Then, 100%.
Profit triples and S.P doubles.
3P = 2S.P - C.P.
3(S.P - C.P) = 2S.P - C.P.
So, S.P = 2C.P.
S.P/C.P = 2/1.
P = 1 / 1*100.
Then, 100%.
Shekhar adhikari said:
10 years ago
Let CP =x and SP = y.
According to the question 3(y - x) = 2y - x.
Here in question this equation 'is given as condition only.S.P is already fixed.
This condition connects between SP and Cp from this condition we get the relation betweenSP and Cp as y = 2x .
Then we should take profit => y - x = 2x - x = x.
Thus profit % = x/x *100 = 100%.
According to the question 3(y - x) = 2y - x.
Here in question this equation 'is given as condition only.S.P is already fixed.
This condition connects between SP and Cp from this condition we get the relation betweenSP and Cp as y = 2x .
Then we should take profit => y - x = 2x - x = x.
Thus profit % = x/x *100 = 100%.
Kumar Ghimire said:
10 years ago
Thanks @Niharul Islam.
524@ssh said:
10 years ago
Let cp = x., then sp = 2x.
The profit is (sp - cp)/cp * 100.
(2x - x)/x * 100.
x/x * 100 = 100.
Therefore profit =100.
The profit is (sp - cp)/cp * 100.
(2x - x)/x * 100.
x/x * 100 = 100.
Therefore profit =100.
Govind kumar karn said:
10 years ago
Let C.P.= x, S.P = y.
Then according to the question 3(y - x) = (2y - x).
So y = 2x.
We know that, profit= (S.P - C.P).
=> (y - x) = (2x - x).
=> (x*100)/100 = 100% answered.
Then according to the question 3(y - x) = (2y - x).
So y = 2x.
We know that, profit= (S.P - C.P).
=> (y - x) = (2x - x).
=> (x*100)/100 = 100% answered.
Finny said:
10 years ago
Someone to clarify please?
Mallikarjun said:
10 years ago
Why did we taken 3(y-x) = (2y-x)? Please explain it.
Minakshi said:
10 years ago
This question was asked in AFCAT 2/2015 and I answered 100% but when their answer sheet came out their answer was (199/3)%. I just don't get it.
Niharul Islam said:
10 years ago
We know, Profit (P) = Selling Price (y) - Costing Price (x)....(1).
Given, 3p = 2y - x.
=> p = (2y-X)/3.....(2).
From equation 1 &2 we get,
y - x = (2y-x)/3.
=> 3y - 3x = 2y-x.
=> 3y - 2y = -x + 3x.
=> y = 2x.
We know Profit Equation,
Profit = (y-x)/x.
= (2x - x)/x.
= x/x.
= 1*100% = 100%.
This is the 100% answer of this math.
Given, 3p = 2y - x.
=> p = (2y-X)/3.....(2).
From equation 1 &2 we get,
y - x = (2y-x)/3.
=> 3y - 3x = 2y-x.
=> 3y - 2y = -x + 3x.
=> y = 2x.
We know Profit Equation,
Profit = (y-x)/x.
= (2x - x)/x.
= x/x.
= 1*100% = 100%.
This is the 100% answer of this math.
Suganya Dinesh said:
10 years ago
Don't confuse with X & Y.
Simple method is:
SP is doubled so 200. Profit is triples so 300. Hence CP is surely be 100.
Then work out formula:
Gain = SP - CP ; 200 - 100 = 100%.
Simple method is:
SP is doubled so 200. Profit is triples so 300. Hence CP is surely be 100.
Then work out formula:
Gain = SP - CP ; 200 - 100 = 100%.
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