Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) 
y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
 Profit % = |
 |
x | x 100 |  % = 100% |
| x |
Video Explanation: https://youtu.be/dPzF10mGsWE
Discussion:
304 comments Page 18 of 31.
Govind kumar karn said:
9 years ago
Let C.P.= x, S.P = y.
Then according to the question 3(y - x) = (2y - x).
So y = 2x.
We know that, profit= (S.P - C.P).
=> (y - x) = (2x - x).
=> (x*100)/100 = 100% answered.
Then according to the question 3(y - x) = (2y - x).
So y = 2x.
We know that, profit= (S.P - C.P).
=> (y - x) = (2x - x).
=> (x*100)/100 = 100% answered.
Finny said:
9 years ago
Someone to clarify please?
Mallikarjun said:
9 years ago
Why did we taken 3(y-x) = (2y-x)? Please explain it.
Minakshi said:
9 years ago
This question was asked in AFCAT 2/2015 and I answered 100% but when their answer sheet came out their answer was (199/3)%. I just don't get it.
Niharul Islam said:
9 years ago
We know, Profit (P) = Selling Price (y) - Costing Price (x)....(1).
Given, 3p = 2y - x.
=> p = (2y-X)/3.....(2).
From equation 1 &2 we get,
y - x = (2y-x)/3.
=> 3y - 3x = 2y-x.
=> 3y - 2y = -x + 3x.
=> y = 2x.
We know Profit Equation,
Profit = (y-x)/x.
= (2x - x)/x.
= x/x.
= 1*100% = 100%.
This is the 100% answer of this math.
Given, 3p = 2y - x.
=> p = (2y-X)/3.....(2).
From equation 1 &2 we get,
y - x = (2y-x)/3.
=> 3y - 3x = 2y-x.
=> 3y - 2y = -x + 3x.
=> y = 2x.
We know Profit Equation,
Profit = (y-x)/x.
= (2x - x)/x.
= x/x.
= 1*100% = 100%.
This is the 100% answer of this math.
Suganya Dinesh said:
9 years ago
Don't confuse with X & Y.
Simple method is:
SP is doubled so 200. Profit is triples so 300. Hence CP is surely be 100.
Then work out formula:
Gain = SP - CP ; 200 - 100 = 100%.
Simple method is:
SP is doubled so 200. Profit is triples so 300. Hence CP is surely be 100.
Then work out formula:
Gain = SP - CP ; 200 - 100 = 100%.
Sunny SHarma said:
10 years ago
Look,
Take SP = 1, then new SP = 2.
So, old profit, p = (1-CP)/CP ---> equation 1.
And new profit, 3p = (2-CP)/CP ---> equation 2.
Divide equation 1 by equation 2 and solve for CP = 1/2, thus profit = 100%.
Take SP = 1, then new SP = 2.
So, old profit, p = (1-CP)/CP ---> equation 1.
And new profit, 3p = (2-CP)/CP ---> equation 2.
Divide equation 1 by equation 2 and solve for CP = 1/2, thus profit = 100%.
Ayinoluwa oladayiye said:
10 years ago
I don't understand why or how the answer is 100 because there is 3x and 2y. Can you explain it fluently?
Ramya.k said:
10 years ago
Let profit be 'p', S.P be 'y' and C.P be 'x'.
Now we know that profit = S.P-C.P.
i.e, p = y-x ----- (1) (say);
Now according to problem 3p = 2y-x--- (2) (say).
Now substitute (1) in (2).
Then, 3(y-x) = 2y-x;
3y-3x = 2y-x;
3y-2y = 3x-x;
y = 2x---- (3) (say);
Now put (3) in (1);
Then p = 2x-x;
Now p% = ((2x-x)/x)*100;
P% = (x/x)*100;
P% = 100;
Now we know that profit = S.P-C.P.
i.e, p = y-x ----- (1) (say);
Now according to problem 3p = 2y-x--- (2) (say).
Now substitute (1) in (2).
Then, 3(y-x) = 2y-x;
3y-3x = 2y-x;
3y-2y = 3x-x;
y = 2x---- (3) (say);
Now put (3) in (1);
Then p = 2x-x;
Now p% = ((2x-x)/x)*100;
P% = (x/x)*100;
P% = 100;
Manoj said:
10 years ago
C.P. = 100, S.P. = 200.
Profit = S.P. - C.P.
= 200 - 100 = 100.
Profit% = 100*100/100 = 100%.
Profit = S.P. - C.P.
= 200 - 100 = 100.
Profit% = 100*100/100 = 100%.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers