Aptitude - Profit and Loss - Discussion

Hi, l am Bharathi, how comes 3 (y-x) and (2y-x).

Most of you get confused by this question because you think that we have to find the profit percentage when the selling price is doubled.

But it's not like that.

They have just given a clue to assume how to take profit.

Let's take C. P as x and S. P as why;
We know that profit is S. P - C. P.
Twice the selling price is not equal to thrice the profit.

2y - x = 3(y - x).

Here, when selling price is doubled (2y) , at that time the profit i.e., (2y - x) is equal to thrice normal profit value3 (y - x).

Then simplifying this 2y - x = 3 (y - x), you will get y = 2x.
Hope you will do the remaining.

For all who don't understand.

Let,

A = Cost price.

B = Selling price.

C = b - a = Profit.

When selling price is doubled;

Cost price = a.

Selling price = 2b.

Profit = 2b-a --------> (1).

Given that when selling price is doubled, the profit triples;

Ie profit = (b - a) x 3 = 3b - 3a --------> (2).

Equation (1) and (2) are equal, on equating;

3b - 3a = 2b - a ie b = 2a.

B = 2a means the selling price is twice as that of the cost price, which means the profit is another 'a'. (ie) 100%.

When I read all the comments, I understood one thing.

Everyone reads the question in a different way.

I can't understand the problem. Please help me.

@Rajiya.

Good Explanation. Thank you.

P = S.P - C.P.

Profit triples and S.P doubles.

3P = 2S.P - C.P.

3(S.P - C.P) = 2S.P - C.P.

So, S.P = 2C.P.

S.P/C.P = 2/1.

P = 1 / 1*100.

Then, 100%.

Let CP =x and SP = y.

According to the question 3(y - x) = 2y - x.
Here in question this equation 'is given as condition only.S.P is already fixed.
This condition connects between SP and Cp from this condition we get the relation betweenSP and Cp as y = 2x .

Then we should take profit => y - x = 2x - x = x.
Thus profit % = x/x *100 = 100%.

Thanks @Niharul Islam.

Let cp = x., then sp = 2x.

The profit is (sp - cp)/cp * 100.
(2x - x)/x * 100.
x/x * 100 = 100.

Therefore profit =100.