Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) 
y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
 Profit % = |
 |
x | x 100 |  % = 100% |
| x |
Video Explanation: https://youtu.be/dPzF10mGsWE
Discussion:
306 comments Page 17 of 31.
Sunny SHarma said:
10 years ago
Look,
Take SP = 1, then new SP = 2.
So, old profit, p = (1-CP)/CP ---> equation 1.
And new profit, 3p = (2-CP)/CP ---> equation 2.
Divide equation 1 by equation 2 and solve for CP = 1/2, thus profit = 100%.
Take SP = 1, then new SP = 2.
So, old profit, p = (1-CP)/CP ---> equation 1.
And new profit, 3p = (2-CP)/CP ---> equation 2.
Divide equation 1 by equation 2 and solve for CP = 1/2, thus profit = 100%.
Suganya Dinesh said:
10 years ago
Don't confuse with X & Y.
Simple method is:
SP is doubled so 200. Profit is triples so 300. Hence CP is surely be 100.
Then work out formula:
Gain = SP - CP ; 200 - 100 = 100%.
Simple method is:
SP is doubled so 200. Profit is triples so 300. Hence CP is surely be 100.
Then work out formula:
Gain = SP - CP ; 200 - 100 = 100%.
Niharul Islam said:
10 years ago
We know, Profit (P) = Selling Price (y) - Costing Price (x)....(1).
Given, 3p = 2y - x.
=> p = (2y-X)/3.....(2).
From equation 1 &2 we get,
y - x = (2y-x)/3.
=> 3y - 3x = 2y-x.
=> 3y - 2y = -x + 3x.
=> y = 2x.
We know Profit Equation,
Profit = (y-x)/x.
= (2x - x)/x.
= x/x.
= 1*100% = 100%.
This is the 100% answer of this math.
Given, 3p = 2y - x.
=> p = (2y-X)/3.....(2).
From equation 1 &2 we get,
y - x = (2y-x)/3.
=> 3y - 3x = 2y-x.
=> 3y - 2y = -x + 3x.
=> y = 2x.
We know Profit Equation,
Profit = (y-x)/x.
= (2x - x)/x.
= x/x.
= 1*100% = 100%.
This is the 100% answer of this math.
Minakshi said:
10 years ago
This question was asked in AFCAT 2/2015 and I answered 100% but when their answer sheet came out their answer was (199/3)%. I just don't get it.
Mallikarjun said:
10 years ago
Why did we taken 3(y-x) = (2y-x)? Please explain it.
Finny said:
10 years ago
Someone to clarify please?
Govind kumar karn said:
9 years ago
Let C.P.= x, S.P = y.
Then according to the question 3(y - x) = (2y - x).
So y = 2x.
We know that, profit= (S.P - C.P).
=> (y - x) = (2x - x).
=> (x*100)/100 = 100% answered.
Then according to the question 3(y - x) = (2y - x).
So y = 2x.
We know that, profit= (S.P - C.P).
=> (y - x) = (2x - x).
=> (x*100)/100 = 100% answered.
524@ssh said:
9 years ago
Let cp = x., then sp = 2x.
The profit is (sp - cp)/cp * 100.
(2x - x)/x * 100.
x/x * 100 = 100.
Therefore profit =100.
The profit is (sp - cp)/cp * 100.
(2x - x)/x * 100.
x/x * 100 = 100.
Therefore profit =100.
Kumar Ghimire said:
9 years ago
Thanks @Niharul Islam.
Shekhar adhikari said:
9 years ago
Let CP =x and SP = y.
According to the question 3(y - x) = 2y - x.
Here in question this equation 'is given as condition only.S.P is already fixed.
This condition connects between SP and Cp from this condition we get the relation betweenSP and Cp as y = 2x .
Then we should take profit => y - x = 2x - x = x.
Thus profit % = x/x *100 = 100%.
According to the question 3(y - x) = 2y - x.
Here in question this equation 'is given as condition only.S.P is already fixed.
This condition connects between SP and Cp from this condition we get the relation betweenSP and Cp as y = 2x .
Then we should take profit => y - x = 2x - x = x.
Thus profit % = x/x *100 = 100%.
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