Aptitude - Profit and Loss - Discussion

Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
66 2
3
100
105 1
3
120
Answer: Option
Explanation:

Let C.P. be Rs. x and S.P. be Rs. y.

Then, 3(y - x) = (2y - x)    y = 2x.

Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.

Profit % = x x 100 % = 100%
x

Video Explanation: https://youtu.be/dPzF10mGsWE

Discussion:
306 comments Page 16 of 31.

Ram said:   10 years ago
If selling price doubled we can use only 2y?

Why all are used 2y-x?

Dhanlaxmi said:   10 years ago
Here 2y-x means profit i.e.: S.P - C.P.

Sekar said:   10 years ago
2 S.P = 3 Profit.

2 S.P = 3 S.P - 3 C.P.

S.P = 3 C.P.

Assume C.P Rs. 1.

Profit = 2*100/1.

i.e 200.

Please tel me where I went wrong.

Priyanshe said:   10 years ago
Suppose C.P is 100.

And in the question given S.P is doubled means S.P is 200.

And Profit is triples i.e. 300.

So, the formula is %profit = S.P-C.P/C.P*100.

= 200-100/100*100 = 100.

Ketema said:   10 years ago
@Pooja.

Thanks. this simple why other persons going round? If profit is tripled & S.P is doubled then what is the gain percentage?

As @Pooja explain,

G% = 100 (S.P-C.P)/C.P.

W\c is 100 (2x-x)/x.

Since S.P or y = 2x and C.P = x. So G% = 100%.

Karthik said:   10 years ago
Let cp = x, sp = y.

We know profit = profit.

y-x = y-x.

If sp is doubled then according to the condition profit gets tripled.

2y-x = 3(y-x).

y = 2x.

Then gain = 100*y-x/x = (2x-x)*100/x = 100%.

Naseem Saifi said:   10 years ago
Given that,

S.P = 2*C.P______ (1).

Profit = 3*C.P___ (2).

We know that profit = S.P-C.P [Formula 4 profit].

=> profit = 2*C.P-C.P = C.P___ (3) [From 1st S.P = 2*C.P].

Profit% = Profit/C.P*100 [Formula 4 profit%].

= C.P/C.P*100 = 100.

Manoj said:   10 years ago
C.P. = 100, S.P. = 200.

Profit = S.P. - C.P.

= 200 - 100 = 100.

Profit% = 100*100/100 = 100%.

Ramya.k said:   10 years ago
Let profit be 'p', S.P be 'y' and C.P be 'x'.

Now we know that profit = S.P-C.P.

i.e, p = y-x ----- (1) (say);

Now according to problem 3p = 2y-x--- (2) (say).

Now substitute (1) in (2).

Then, 3(y-x) = 2y-x;

3y-3x = 2y-x;

3y-2y = 3x-x;

y = 2x---- (3) (say);

Now put (3) in (1);

Then p = 2x-x;

Now p% = ((2x-x)/x)*100;

P% = (x/x)*100;

P% = 100;

Ayinoluwa oladayiye said:   10 years ago
I don't understand why or how the answer is 100 because there is 3x and 2y. Can you explain it fluently?


Post your comments here:

Your comments will be displayed after verification.