Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) 
y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
 Profit % = |
 |
x | x 100 |  % = 100% |
| x |
Video Explanation: https://youtu.be/dPzF10mGsWE
Discussion:
304 comments Page 16 of 31.
Priyanshe said:
10 years ago
Suppose C.P is 100.
And in the question given S.P is doubled means S.P is 200.
And Profit is triples i.e. 300.
So, the formula is %profit = S.P-C.P/C.P*100.
= 200-100/100*100 = 100.
And in the question given S.P is doubled means S.P is 200.
And Profit is triples i.e. 300.
So, the formula is %profit = S.P-C.P/C.P*100.
= 200-100/100*100 = 100.
Ketema said:
10 years ago
@Pooja.
Thanks. this simple why other persons going round? If profit is tripled & S.P is doubled then what is the gain percentage?
As @Pooja explain,
G% = 100 (S.P-C.P)/C.P.
W\c is 100 (2x-x)/x.
Since S.P or y = 2x and C.P = x. So G% = 100%.
Thanks. this simple why other persons going round? If profit is tripled & S.P is doubled then what is the gain percentage?
As @Pooja explain,
G% = 100 (S.P-C.P)/C.P.
W\c is 100 (2x-x)/x.
Since S.P or y = 2x and C.P = x. So G% = 100%.
Karthik said:
10 years ago
Let cp = x, sp = y.
We know profit = profit.
y-x = y-x.
If sp is doubled then according to the condition profit gets tripled.
2y-x = 3(y-x).
y = 2x.
Then gain = 100*y-x/x = (2x-x)*100/x = 100%.
We know profit = profit.
y-x = y-x.
If sp is doubled then according to the condition profit gets tripled.
2y-x = 3(y-x).
y = 2x.
Then gain = 100*y-x/x = (2x-x)*100/x = 100%.
Naseem Saifi said:
10 years ago
Given that,
S.P = 2*C.P______ (1).
Profit = 3*C.P___ (2).
We know that profit = S.P-C.P [Formula 4 profit].
=> profit = 2*C.P-C.P = C.P___ (3) [From 1st S.P = 2*C.P].
Profit% = Profit/C.P*100 [Formula 4 profit%].
= C.P/C.P*100 = 100.
S.P = 2*C.P______ (1).
Profit = 3*C.P___ (2).
We know that profit = S.P-C.P [Formula 4 profit].
=> profit = 2*C.P-C.P = C.P___ (3) [From 1st S.P = 2*C.P].
Profit% = Profit/C.P*100 [Formula 4 profit%].
= C.P/C.P*100 = 100.
Manoj said:
10 years ago
C.P. = 100, S.P. = 200.
Profit = S.P. - C.P.
= 200 - 100 = 100.
Profit% = 100*100/100 = 100%.
Profit = S.P. - C.P.
= 200 - 100 = 100.
Profit% = 100*100/100 = 100%.
Ramya.k said:
10 years ago
Let profit be 'p', S.P be 'y' and C.P be 'x'.
Now we know that profit = S.P-C.P.
i.e, p = y-x ----- (1) (say);
Now according to problem 3p = 2y-x--- (2) (say).
Now substitute (1) in (2).
Then, 3(y-x) = 2y-x;
3y-3x = 2y-x;
3y-2y = 3x-x;
y = 2x---- (3) (say);
Now put (3) in (1);
Then p = 2x-x;
Now p% = ((2x-x)/x)*100;
P% = (x/x)*100;
P% = 100;
Now we know that profit = S.P-C.P.
i.e, p = y-x ----- (1) (say);
Now according to problem 3p = 2y-x--- (2) (say).
Now substitute (1) in (2).
Then, 3(y-x) = 2y-x;
3y-3x = 2y-x;
3y-2y = 3x-x;
y = 2x---- (3) (say);
Now put (3) in (1);
Then p = 2x-x;
Now p% = ((2x-x)/x)*100;
P% = (x/x)*100;
P% = 100;
Ayinoluwa oladayiye said:
10 years ago
I don't understand why or how the answer is 100 because there is 3x and 2y. Can you explain it fluently?
Sunny SHarma said:
10 years ago
Look,
Take SP = 1, then new SP = 2.
So, old profit, p = (1-CP)/CP ---> equation 1.
And new profit, 3p = (2-CP)/CP ---> equation 2.
Divide equation 1 by equation 2 and solve for CP = 1/2, thus profit = 100%.
Take SP = 1, then new SP = 2.
So, old profit, p = (1-CP)/CP ---> equation 1.
And new profit, 3p = (2-CP)/CP ---> equation 2.
Divide equation 1 by equation 2 and solve for CP = 1/2, thus profit = 100%.
Suganya Dinesh said:
10 years ago
Don't confuse with X & Y.
Simple method is:
SP is doubled so 200. Profit is triples so 300. Hence CP is surely be 100.
Then work out formula:
Gain = SP - CP ; 200 - 100 = 100%.
Simple method is:
SP is doubled so 200. Profit is triples so 300. Hence CP is surely be 100.
Then work out formula:
Gain = SP - CP ; 200 - 100 = 100%.
Niharul Islam said:
9 years ago
We know, Profit (P) = Selling Price (y) - Costing Price (x)....(1).
Given, 3p = 2y - x.
=> p = (2y-X)/3.....(2).
From equation 1 &2 we get,
y - x = (2y-x)/3.
=> 3y - 3x = 2y-x.
=> 3y - 2y = -x + 3x.
=> y = 2x.
We know Profit Equation,
Profit = (y-x)/x.
= (2x - x)/x.
= x/x.
= 1*100% = 100%.
This is the 100% answer of this math.
Given, 3p = 2y - x.
=> p = (2y-X)/3.....(2).
From equation 1 &2 we get,
y - x = (2y-x)/3.
=> 3y - 3x = 2y-x.
=> 3y - 2y = -x + 3x.
=> y = 2x.
We know Profit Equation,
Profit = (y-x)/x.
= (2x - x)/x.
= x/x.
= 1*100% = 100%.
This is the 100% answer of this math.
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