Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) 
y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
 Profit % = |
 |
x | x 100 |  % = 100% |
| x |
Video Explanation: https://youtu.be/dPzF10mGsWE
Discussion:
304 comments Page 13 of 31.
Shiti said:
1 decade ago
Take an example we will take LCM of 2 and 3 as it is double and triple so 6 would be selling price profit is tripled so initial profit is 2 and as selling price is doubled initial SP is 3. So CP is 1 I think the profit percentage i.e P/cp x 100 = 2/1 x 100 = 200%.
Shyam said:
1 decade ago
Say CP = 10.
SP = 20 profit will be 10 only.
Then after changing SP twice. It will be 40 right?
So SP*2 = 40.
Now profit = 40-10 = 30. Which is thrice as previous profit?
Then profit % is more 300% is it?
So, I think question need to more descriptive right?
SP = 20 profit will be 10 only.
Then after changing SP twice. It will be 40 right?
So SP*2 = 40.
Now profit = 40-10 = 30. Which is thrice as previous profit?
Then profit % is more 300% is it?
So, I think question need to more descriptive right?
Ravi said:
1 decade ago
C.P = x.
S.P = 2x.
P = 3x.
We know Profit = S.P-C.P.
So Here Profit = 2x-x = x.
We also know Profit% = P/C.Px100.
X/Xx100 = 100%.
S.P = 2x.
P = 3x.
We know Profit = S.P-C.P.
So Here Profit = 2x-x = x.
We also know Profit% = P/C.Px100.
X/Xx100 = 100%.
DDv said:
1 decade ago
Ok look the most basic and fastest way to think.
Take C.P as 100 and sell price as 100+x; where profit is x;
Now 3x = 2*(100+x)-100(C.P);
3x = 100+x;
x = 100;
So on 100 C.P profit 100; so profit is 100%.
Take C.P as 100 and sell price as 100+x; where profit is x;
Now 3x = 2*(100+x)-100(C.P);
3x = 100+x;
x = 100;
So on 100 C.P profit 100; so profit is 100%.
Divya said:
1 decade ago
CP = x, SP = 2x.
Profit = SP-CP = 2x-x = x.
%profit = (profit/CP)*100.
= x/x*100.
= 100.
Profit = SP-CP = 2x-x = x.
%profit = (profit/CP)*100.
= x/x*100.
= 100.
Kehkashaa dubey said:
1 decade ago
I am confused. How would I do it without using x and y?
Could somebody provide me with a logic? When I did it logically it came our to be 200%.
Could somebody provide me with a logic? When I did it logically it came our to be 200%.
DEBLINA DUTTA said:
1 decade ago
Let, CP: 'X' and SP: 'Y' and profit : 'P'.
Then, P= (Y-X) / X ----------- (1).
Now, new SP= '2Y' and new profit : '3P'.
Then, 3P= (2Y-X) / X -------------- (2).
Put the value of 'P' from equation number (1).
So, (2Y-X) / X = (3Y-3X) / X.
Or, 2XY-X^2 = 3XY-3X^2.
Or, Y = 2X.
Put the value of 'Y' in eqn no. (1).
So, (2X-X) / X = P = 1*100 =100.
(ie) 100%.
Then, P= (Y-X) / X ----------- (1).
Now, new SP= '2Y' and new profit : '3P'.
Then, 3P= (2Y-X) / X -------------- (2).
Put the value of 'P' from equation number (1).
So, (2Y-X) / X = (3Y-3X) / X.
Or, 2XY-X^2 = 3XY-3X^2.
Or, Y = 2X.
Put the value of 'Y' in eqn no. (1).
So, (2X-X) / X = P = 1*100 =100.
(ie) 100%.
MRIGANSH MATHUR said:
1 decade ago
Its just this that you can compare only similar things. Like profit with profit.
So, in this case when profit is thrice so SP is doubled.
So when it is equated.
3(y - x) = (2y - x)y = 2x.
In this profit as we know is (y-x) which is thrice.
So when we equate this we equate it with the profit at this time when it is thrice ok.
So the profit at this time would be SP-CP but here SP is twice at q so that is why 2y-x is there.
So, in this case when profit is thrice so SP is doubled.
So when it is equated.
3(y - x) = (2y - x)y = 2x.
In this profit as we know is (y-x) which is thrice.
So when we equate this we equate it with the profit at this time when it is thrice ok.
So the profit at this time would be SP-CP but here SP is twice at q so that is why 2y-x is there.
Akhila said:
1 decade ago
As given in the problem. SP-CP = Profit right.
Consider that SP-CP = (y-x).
Now SP should be double that is 2y-x.
And CP should be triple that is 3(y-x).
That is 2y-x = 3(y-x).
By solving this will get the profit.
Consider that SP-CP = (y-x).
Now SP should be double that is 2y-x.
And CP should be triple that is 3(y-x).
That is 2y-x = 3(y-x).
By solving this will get the profit.
Sara said:
1 decade ago
Hai friends.
Profit means selling price > cost price.
Profit% = (profit/cost price)*100.
Selling price doubles. So we take 2S>1.
So actual cost price is single. So S>2.
Now from profit % formula = ((2S/S)/100)% = 100%.
Profit means selling price > cost price.
Profit% = (profit/cost price)*100.
Selling price doubles. So we take 2S>1.
So actual cost price is single. So S>2.
Now from profit % formula = ((2S/S)/100)% = 100%.
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