Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) 
y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
 Profit % = |
 |
x | x 100 |  % = 100% |
| x |
Video Explanation: https://youtu.be/dPzF10mGsWE
Discussion:
306 comments Page 13 of 31.
Sunil said:
1 decade ago
Let cost price = Rs 1.
Selling price doubled i.e = Rs 2.
Profit triples i.e = Rs 3.
Gain = SP-CP.
= 2-1.
= rs 1/-.
Profit% = gain*100/CP.
= 1*100/1 = 100.
*You take any number it will be true. !
Selling price doubled i.e = Rs 2.
Profit triples i.e = Rs 3.
Gain = SP-CP.
= 2-1.
= rs 1/-.
Profit% = gain*100/CP.
= 1*100/1 = 100.
*You take any number it will be true. !
Rajan said:
1 decade ago
Please any one explain me in detail each and every step.
Shubham said:
1 decade ago
What is the use of saying "Profit triples", it makes question very confusing. If S.P doubles then how can be profit triples?
Shiti said:
1 decade ago
Take an example we will take LCM of 2 and 3 as it is double and triple so 6 would be selling price profit is tripled so initial profit is 2 and as selling price is doubled initial SP is 3. So CP is 1 I think the profit percentage i.e P/cp x 100 = 2/1 x 100 = 200%.
Shyam said:
1 decade ago
Say CP = 10.
SP = 20 profit will be 10 only.
Then after changing SP twice. It will be 40 right?
So SP*2 = 40.
Now profit = 40-10 = 30. Which is thrice as previous profit?
Then profit % is more 300% is it?
So, I think question need to more descriptive right?
SP = 20 profit will be 10 only.
Then after changing SP twice. It will be 40 right?
So SP*2 = 40.
Now profit = 40-10 = 30. Which is thrice as previous profit?
Then profit % is more 300% is it?
So, I think question need to more descriptive right?
Ravi said:
1 decade ago
C.P = x.
S.P = 2x.
P = 3x.
We know Profit = S.P-C.P.
So Here Profit = 2x-x = x.
We also know Profit% = P/C.Px100.
X/Xx100 = 100%.
S.P = 2x.
P = 3x.
We know Profit = S.P-C.P.
So Here Profit = 2x-x = x.
We also know Profit% = P/C.Px100.
X/Xx100 = 100%.
DDv said:
1 decade ago
Ok look the most basic and fastest way to think.
Take C.P as 100 and sell price as 100+x; where profit is x;
Now 3x = 2*(100+x)-100(C.P);
3x = 100+x;
x = 100;
So on 100 C.P profit 100; so profit is 100%.
Take C.P as 100 and sell price as 100+x; where profit is x;
Now 3x = 2*(100+x)-100(C.P);
3x = 100+x;
x = 100;
So on 100 C.P profit 100; so profit is 100%.
Divya said:
1 decade ago
CP = x, SP = 2x.
Profit = SP-CP = 2x-x = x.
%profit = (profit/CP)*100.
= x/x*100.
= 100.
Profit = SP-CP = 2x-x = x.
%profit = (profit/CP)*100.
= x/x*100.
= 100.
Kehkashaa dubey said:
1 decade ago
I am confused. How would I do it without using x and y?
Could somebody provide me with a logic? When I did it logically it came our to be 200%.
Could somebody provide me with a logic? When I did it logically it came our to be 200%.
DEBLINA DUTTA said:
1 decade ago
Let, CP: 'X' and SP: 'Y' and profit : 'P'.
Then, P= (Y-X) / X ----------- (1).
Now, new SP= '2Y' and new profit : '3P'.
Then, 3P= (2Y-X) / X -------------- (2).
Put the value of 'P' from equation number (1).
So, (2Y-X) / X = (3Y-3X) / X.
Or, 2XY-X^2 = 3XY-3X^2.
Or, Y = 2X.
Put the value of 'Y' in eqn no. (1).
So, (2X-X) / X = P = 1*100 =100.
(ie) 100%.
Then, P= (Y-X) / X ----------- (1).
Now, new SP= '2Y' and new profit : '3P'.
Then, 3P= (2Y-X) / X -------------- (2).
Put the value of 'P' from equation number (1).
So, (2Y-X) / X = (3Y-3X) / X.
Or, 2XY-X^2 = 3XY-3X^2.
Or, Y = 2X.
Put the value of 'Y' in eqn no. (1).
So, (2X-X) / X = P = 1*100 =100.
(ie) 100%.
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