Aptitude - Profit and Loss - Discussion

Let 1st S.P = 100, profit - 1x, and 2nd S.P = 200,
If profit is tripled then it is 3x.

Therefore 3x-1x= 2x,
x = 200/2.
x = 100.

Really I am confusing about this question. Because Q)If selling price is doubled, the profit triples. Find the profit percent.

SP double means we always determined SP on CP. So obviously CP = x and SP = 2x.
And profit always depend upon diff btw SP and CP. So Profit = x.

But according to question profit = 3X.

Then profit% = (profit/CP)*100.

If profit = X then P%= 100%.

But as per question p=3X so profit = (3x/x)*100 = 300%.

How is it possible. Please clarify my doubt?

No need that much solution.

Let CP = 1 Rs.
Then SP = 2 rs (because double).

Leave profit is triple. no need to take,
That's why profit % is 100% (because double).

We know that SP = CP + profit........1.
Now given 2 SP = CP + 3 profit........2.

ON solving these equation we get that,
S.P = 2 profit.

Now in equation SP-CP/CP*100.
Answer is 100%.

SP = x;
CP = y;
p = (x-y) * 100 / y;
SP' = 2x;
P' = 3*P;

=> (2x-y) * 100 / y = 3 * (x-y) * 100 / y;
=> x = 2 * y;
=> SP = 2 * CP;
=> P = 100%;
=> Profit Percent = 100%.

Give me inform what is the process in this question?

Assume C.P = x.
//Then selling price is double.

Means S.P = 2x.
Profit = (S.P - C.P).
So profit = 2x-x = x.

%Profit = prifit*100/C.P.
= x*100/x.
= 100.

SP = x;
CP = y;
p = (x-y)*100/y;

SP' = 2x;
P' = 3*P;

=> (2x-y)*100/y = 3*(x-y)*100/y;

=> x = 2*y;
=> SP = 2*CP;

=> P = 100%;
=> Profit Percent = 100%.

Let CP = x;
SP = 2x;

Profit = SP-CP;
Profit = 2x-x;
Profit = x;

Gain% = (gain*100/cp);
Gain% = (x*100/X);
Gain% = 100;

@Pooja but just for clarification.

If you calculate the profit it will not be tripled !

They should add one more option as 300%

If you buy a pencil for 5 rs sell it for 10rs you have a profit of 5rs that's 100% profit !

CP = 5rs.
SP(doubled) = 20rs.
Profit = 20-5 = 15rs.
Profit is thrice the profit it was before 5x3.

Then profit becomes 300%