Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 30)
30.
Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
9 a.m.
10 a.m.
10.30 a.m.
11 a.m.
Answer: Option
Explanation:

Suppose they meet x hours after 7 a.m.

Distance covered by A in x hours = 20x km.

Distance covered by B in (x - 1) hours = 25(x - 1) km.

Therefore 20x + 25(x - 1) = 110

=> 45x = 135

=> x = 3.

So, they meet at 10 a.m.

Discussion:
92 comments Page 8 of 10.

Prasoon Kumar said:   3 years ago
I didn't get anything. Please help me to get this.
(3)

Shalini said:   1 year ago
It's very interesting and useful to learn. Thanks.
(3)

Jammy said:   1 decade ago
3 = 3 hour.....therefore 7 a.m + 3 hour = 10 a.m

Mary said:   8 years ago
How to solve if they move in the same direction?

Mano said:   6 years ago
How we are obtained the 10 ?

Please explain it.
(1)

Keerthu said:   9 years ago
Hi, @Chai.

I got 1:25 PM. Is this correct?

Arun said:   1 decade ago
@Chai.

Answer : 2.15 pm. Is this correct?

Gokul Ramakrishnan said:   4 years ago
@Chai.

I got 2.25 is it correct or not?
(1)

Asmi said:   4 years ago
Here, how will get 110? Please explain.

Teena said:   1 decade ago
I dint get how x-1 term is used.


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