Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 30)
30.
Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
Answer: Option
Explanation:
Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
20x + 25(x - 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.
Discussion:
92 comments Page 7 of 10.
Sathya said:
2 decades ago
Though the train B starts 1 hour late than train A, The speed of the train varies.
Syed Abdul Raqeeb said:
5 years ago
Why x-1 is used in this sum, and how x=3 and how the answer is 10? Please explain.
(1)
Akshay k said:
4 years ago
Tell me that these two trains meet at what distance. Please anyone explain to me.
(3)
Amit Kumar said:
1 decade ago
Dear Arun,
Because train is started 1 hours late, thats why x-1
Because train is started 1 hours late, thats why x-1
Sonic said:
9 years ago
Why it's taken x-1 but not x+1 because train 2 starts 1 hr later?
Sonic said:
9 years ago
Why it's taken x-1 but not x+1 because train 2 starts 1 hr later?
Raja said:
9 years ago
Here x=3 is answer how to convert into am/pm some other problem.
Nithi said:
1 decade ago
@Randhir
I too not getting tht 6y concept..pls explain me...
I too not getting tht 6y concept..pls explain me...
Rabiul said:
9 years ago
Thanks @Manish Dabhi.
Your explanation is very useful.
Your explanation is very useful.
Anusha said:
1 decade ago
How x=3 is converted into 10, please tell me any one.
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