Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 30)
30.
Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
Answer: Option
Explanation:
Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
20x + 25(x - 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.
Discussion:
92 comments Page 6 of 10.
Basharat said:
8 years ago
This is based on relative speed.
If they are in opposite directions just add their speeds if they are in same directions subtract their speeds.
If they are in opposite directions just add their speeds if they are in same directions subtract their speeds.
Yogi said:
1 decade ago
Actually I didn't understand this problem how do you get 10 AM as answer please would anyone get rid of these problem am not getting it.
Sudha said:
1 decade ago
@Nayana,
We know that distance= speed*time
So, distance = y*6 = 6y
Calculate time between 5pm and 11pm, so totally 6 hours.
Thanks.
We know that distance= speed*time
So, distance = y*6 = 6y
Calculate time between 5pm and 11pm, so totally 6 hours.
Thanks.
Easwar said:
1 decade ago
Hi Erererer,
It was assumed that trains r meeting after x hours,
so 5 pm(starting time) + 3.20 = 8.20pm
Thanks Randhir.....
It was assumed that trains r meeting after x hours,
so 5 pm(starting time) + 3.20 = 8.20pm
Thanks Randhir.....
Arun said:
1 decade ago
@Chai.
Sorry I will be confused. I got two answers by solving two different methods.
I got 2.15 pm and also I got 4.15 pm.
Sorry I will be confused. I got two answers by solving two different methods.
I got 2.15 pm and also I got 4.15 pm.
Murli Manohar said:
6 years ago
Let they meet X hrs from the 8 a.m.
Then,
110 * 1000 = 20 * (5/18) * 3600 + 45(5/18) * X.
X=2.
So, time= 8+2 = 10 a.m.
Then,
110 * 1000 = 20 * (5/18) * 3600 + 45(5/18) * X.
X=2.
So, time= 8+2 = 10 a.m.
Sachin said:
8 years ago
Here
V1 =20 km/hr.
V2 = 25km/hr.
Time of meet they
= 110-20/20 + 25.
= 2hr.
Then 8+2 = 10am.
V1 =20 km/hr.
V2 = 25km/hr.
Time of meet they
= 110-20/20 + 25.
= 2hr.
Then 8+2 = 10am.
Baswaraj said:
1 decade ago
So x = 3.
Then B start 7 a.m so count three numbers like 8,9,10 (after 7 we will get 8) :10 a.m.
Then B start 7 a.m so count three numbers like 8,9,10 (after 7 we will get 8) :10 a.m.
Anith kumar said:
10 years ago
How we assume x=3 then how we get both meeting time at 10 please explain clearly to me.
Rups said:
9 years ago
If the train was late by 3 hours and 12 minutes, then calculate the nearest hours.
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