Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 30)
30.
Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
9 a.m.
10 a.m.
10.30 a.m.
11 a.m.
Answer: Option
Explanation:

Suppose they meet x hours after 7 a.m.

Distance covered by A in x hours = 20x km.

Distance covered by B in (x - 1) hours = 25(x - 1) km.

Therefore 20x + 25(x - 1) = 110

=> 45x = 135

=> x = 3.

So, they meet at 10 a.m.

Discussion:
92 comments Page 5 of 10.

Mahe said:   1 decade ago
@Faisel,

If they meet 8am then

Distance covered by b in xhrs is 25x
Distance covered by a in(X+1)HRS=20(X+1)
(x+1) coz v r considering 1 hr aft train A has started..

So,
25X+20(X+1)=110
45X=90
X=2

Hence 8am + 2 = 10am

Chai said:   1 decade ago
A and B are two stations 390 km a part. A train start from A at 10 AM and travels towards B at 65 kmph. Another train start from B at 11 AM and travels towards A at 35 kmph. At what time do they meet? Solve this problem.

Ankita said:   9 years ago
Distance between two stations A and B is 100 km, two trains with speed 60 km/h and 40 km/h are running towards each other. What is the distance from station A where both trains will meet?

Can anyone find the answer?

Chings said:   6 years ago
2 station A and B are 110km apart.
1 train start from A at 7 am towards B at 20 kmph 110-20 = 90.

Next one start from B at 8 a.m towards A at 25kmph.
20+25 =45.

Now 90/45 = 2hrs.
.`. 8+2 = 10 a.m.
(2)

Faisal said:   1 decade ago
what if we say they meet after 8AM
Distance covered by B in x Hrs =25X
Distance covered by A in (x-1)Hrs = 20(x-1)
25x+20(x-1)=110
25x+20x-20=110
25x+20x=130
45x=130
x= 2.8 ( Which in incorrect how come )

Likhit D Naik said:   5 years ago
Hey @Syed.

x-1 is used because the second train starts one hour after the first train.

When X=3 is the time in hours to meet. The starting time is 7 a.m so add 3 to it is 10 a.m when the trains meet.
(2)

Damodar Narayan said:   1 decade ago
A----------110---------B 7am

A---------90--------B 8am(Speed of the 1st train is 20 km/h)

A----45----B 9am(relative speed=20+25(45) km/h)

AB 10am

R v said:   1 decade ago
One train will cover 20 km in one hour.

Now the distance remaining is 90 km.

So time take is equal to 90/20+25 = 2 hours means will meet 2 hours after 8 am i.e. 10 am.

Hardik khatri said:   10 years ago
@Chai.

Why do we have to take the distance 390 when we add this covered by A after x hours and this covered by B after x-1 hours then why we equal it to 390 km?

Nayana said:   1 decade ago
@Randhir

In the problem what you have solved above,the distance between point A and B is 6Y. I am not getting how you got 6Y. Can you please explain me that?


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