Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 30)
30.
Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
Answer: Option
Explanation:
Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
20x + 25(x - 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.
Discussion:
92 comments Page 4 of 10.
Easwar said:
1 decade ago
A train leaves a point A at 5 p.m. and reaches another point B a 11 p.m. Another train leaves point B at 7 p.m. and reaches point A at 10 p.m. At what time will the two trains meet?
8 : 15 p.m.
8 : 30 p.m.
8 : 20 p.m.
8 : 00 p.m.
can anyone solve this problem
8 : 15 p.m.
8 : 30 p.m.
8 : 20 p.m.
8 : 00 p.m.
can anyone solve this problem
Manisha said:
7 years ago
A train travels in one houe=20 km.
Now at 8 o'clock distance between tow trains = 90 km.
It is relavent to these two trains speed =20+25km/h = 45km/h.
Now time = distance/speed.
= 90/45 = 2h.
Hence trains meet after 2hours that is 8+2 = 10 a.m.
Now at 8 o'clock distance between tow trains = 90 km.
It is relavent to these two trains speed =20+25km/h = 45km/h.
Now time = distance/speed.
= 90/45 = 2h.
Hence trains meet after 2hours that is 8+2 = 10 a.m.
(1)
Buddhikawd said:
1 decade ago
A_________________110KM______________________B.
7.00 AM. 8.00 AM.
20 KMH. 25 KMh.
2nd train after 1 hour.
So 1st train gone to 20 km.
Because totally 110-20 = 90 km.
Now 20 kmh+25 kmh = 45 kmh.
90/45 = 2 hours.
Now we count 8.00 am+ 2 hours = 10.00 AM.
7.00 AM. 8.00 AM.
20 KMH. 25 KMh.
2nd train after 1 hour.
So 1st train gone to 20 km.
Because totally 110-20 = 90 km.
Now 20 kmh+25 kmh = 45 kmh.
90/45 = 2 hours.
Now we count 8.00 am+ 2 hours = 10.00 AM.
Chittaranjan said:
8 years ago
A_________________110KM______________________B.
7.00 AM. 8.00 AM.
20 KMH. 25 KMh.
2nd train after 1 hour.
So 1st train gone to 20 km.
Because totally 110-20 = 90 km.
Now 20 kmh+25 kmh = 45 kmh.
90/45 = 2 hours.
Now we count 8.00 am+ 2 hours = 10.00 AM.
7.00 AM. 8.00 AM.
20 KMH. 25 KMh.
2nd train after 1 hour.
So 1st train gone to 20 km.
Because totally 110-20 = 90 km.
Now 20 kmh+25 kmh = 45 kmh.
90/45 = 2 hours.
Now we count 8.00 am+ 2 hours = 10.00 AM.
Amit Kr. SONI said:
2 decades ago
Hi Shri,
We can write here
(X-1) b'coz train 'B' starts travelling 1 hr later agains train 'A'.
So, At the end, train B will travel 1 hr short, out of full running time to meet each other. i.e 'X'
So, we can write total time for train 'B' = (X-1)
Thanks
We can write here
(X-1) b'coz train 'B' starts travelling 1 hr later agains train 'A'.
So, At the end, train B will travel 1 hr short, out of full running time to meet each other. i.e 'X'
So, we can write total time for train 'B' = (X-1)
Thanks
Bhat ashraf said:
9 years ago
The difference of speeds of two trains P & Q is 20km/hr. Train P & Q start from points A & B & move towards each other. If the trains meet each other after 2 hr of the journey. What is the speed of the faster train?
Please answer it.
Please answer it.
Manish Dabhi said:
1 decade ago
Train A Travel in 1 hour 20 km at 7 am.
They both started together 8 am.
That's why 110-20 = 90km Remaining,
Relative Speed = (20+25) = 45 km/hr.
Time = (Distance/Speed).
= (90/45)
= 2 Hours
That's why 8am + 2 hours = 10 am.
They both started together 8 am.
That's why 110-20 = 90km Remaining,
Relative Speed = (20+25) = 45 km/hr.
Time = (Distance/Speed).
= (90/45)
= 2 Hours
That's why 8am + 2 hours = 10 am.
Ajay said:
1 decade ago
Its Simple in another way that Total Distance was 110KM.... A start at 7 AM at the speed of 20 KM in 3 Hrs he will cover 60KMS whereas B start at 8 AM @ speed of 25 KM/Per Hour in 2 HRS he will covered 50 KMS that means 7+3=10AM
Charles @ Redhills said:
1 decade ago
@Joicy.
The train B starts an hour later than the train A. Thus the train time A is assumed as x (started at 7 am) and the train B starts at time 8 am which is later an hour of time x hence its x-1. Hope its clear to you now.
The train B starts an hour later than the train A. Thus the train time A is assumed as x (started at 7 am) and the train B starts at time 8 am which is later an hour of time x hence its x-1. Hope its clear to you now.
Sourav Pal said:
9 years ago
Simple formula to be remembered.
Total Time Taken = (d = s2 * t)/s1 + s2.
Where d = 110km, s2 = 25kmph, s1 = 20kmph, t = (8:00am - 7:00am) = 1hr.
From that we get 3hrs.
Therefore required Time is (7:00am + 3hrs) = 10:00Am.
Total Time Taken = (d = s2 * t)/s1 + s2.
Where d = 110km, s2 = 25kmph, s1 = 20kmph, t = (8:00am - 7:00am) = 1hr.
From that we get 3hrs.
Therefore required Time is (7:00am + 3hrs) = 10:00Am.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers