Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 30)
30.
Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
Answer: Option
Explanation:
Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
20x + 25(x - 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.
Discussion:
92 comments Page 3 of 10.
Naresh said:
9 years ago
The distance between two stations A and B is 110km.
1st Train starts at 7am at station A at a speed of 20kmph.
i.e. 1st train travels 20 kms in one hour.
Now The distance is 90kms.
2nd train stats at 8am at and travelling at a speed of 25kmph.
So, the Relative speed of two trains is 20 + 25 = 45kmph.
=> Time = Distance/Speed.
Time = 90/45 = 2hrs.
Requied answer is 8 A.M + 2hr =10 A.M.
1st Train starts at 7am at station A at a speed of 20kmph.
i.e. 1st train travels 20 kms in one hour.
Now The distance is 90kms.
2nd train stats at 8am at and travelling at a speed of 25kmph.
So, the Relative speed of two trains is 20 + 25 = 45kmph.
=> Time = Distance/Speed.
Time = 90/45 = 2hrs.
Requied answer is 8 A.M + 2hr =10 A.M.
Shiv said:
12 months ago
As A train starts at 7 am at 20kmph and B starts at 8 am at 25kmph.
The distance between them is 110 km.
As A starts an hour early at 8 am, A has travelled 20 km.
Now at 8 am, the distance between them is 110–20 km.
As of now, we have a distance as 90 km.
The relative speed is 45kmph.
Time = Distance/Speed.
Time = 90/45 = 2 hrs.
i.e after 2 hours, so 8 a.m + 2 hours = 10 a.m.
The distance between them is 110 km.
As A starts an hour early at 8 am, A has travelled 20 km.
Now at 8 am, the distance between them is 110–20 km.
As of now, we have a distance as 90 km.
The relative speed is 45kmph.
Time = Distance/Speed.
Time = 90/45 = 2 hrs.
i.e after 2 hours, so 8 a.m + 2 hours = 10 a.m.
(38)
Viswa said:
7 years ago
For equal starting time of two trains (ie 8am, 8am).
Train A cover a distance in one hour = 20km.
So total distance covered by two trains =110-20.
= 90km.
The relative speed of trains =20+25.
= 45kmph.
Two trains are meeting at a time of X hr.
The formula is;
90/X = 45,
X=2,
8am+2 = 10am.
Train A cover a distance in one hour = 20km.
So total distance covered by two trains =110-20.
= 90km.
The relative speed of trains =20+25.
= 45kmph.
Two trains are meeting at a time of X hr.
The formula is;
90/X = 45,
X=2,
8am+2 = 10am.
Mohammed Nadhil said:
7 months ago
My logic answer:
At 7, distance covered, A =0 km, B = 0 km.
At 8, distance covered A = 20 km, B =0 km.
At 9, distance covered A = 40 km, B = 25 km.
At 10, distance covered, A = 60 km, B = 50 km.
At 11, distance covered, A = 80 km, B = 75 Km.
At 12, distance covered, A =100 Km, B = 100 k.
Correct me, if my logic is wrong.
At 7, distance covered, A =0 km, B = 0 km.
At 8, distance covered A = 20 km, B =0 km.
At 9, distance covered A = 40 km, B = 25 km.
At 10, distance covered, A = 60 km, B = 50 km.
At 11, distance covered, A = 80 km, B = 75 Km.
At 12, distance covered, A =100 Km, B = 100 k.
Correct me, if my logic is wrong.
(12)
Raj said:
4 years ago
As A train starts at 7 am at 20kmph and B starts at 8 am at 25kmph.
The distance between them is 110km.
As A starts an hour early at 8 am A has travelled 20 km.
Now at 8 am distance between them is (110-20)km.
As of now we have a distance as 90km.
The relative speed is 45kmph.
Time = Distance/Speed.
Time = 90/45 =2 hrs.
The distance between them is 110km.
As A starts an hour early at 8 am A has travelled 20 km.
Now at 8 am distance between them is (110-20)km.
As of now we have a distance as 90km.
The relative speed is 45kmph.
Time = Distance/Speed.
Time = 90/45 =2 hrs.
(33)
Govinda said:
1 decade ago
Its very simple.
Train A start at 7 AM & B start at 8 AM. A travels 20 km in 1 hr ie, distance between A and B will be.
90 Km at 8 AM.
Relative speed = 20+25 = 45Km/hr.
Distance = 90km.
Time = 90/45 = 2 hr.
Total time = 2+1 (that was travelled by train A between 7 to 8 AM. ).
Answer will be 7+3 = 10 AM.
Train A start at 7 AM & B start at 8 AM. A travels 20 km in 1 hr ie, distance between A and B will be.
90 Km at 8 AM.
Relative speed = 20+25 = 45Km/hr.
Distance = 90km.
Time = 90/45 = 2 hr.
Total time = 2+1 (that was travelled by train A between 7 to 8 AM. ).
Answer will be 7+3 = 10 AM.
Gai3 said:
1 decade ago
According to this problem first we have to consider that both trains A & B are start at same time then only we can arrive the answer.
In question it is given that, A train starts at 7 a.m. and B train starts at 8 a.m.
Let starting time for A train = x
and starting time for B train = x-1 .
In question it is given that, A train starts at 7 a.m. and B train starts at 8 a.m.
Let starting time for A train = x
and starting time for B train = x-1 .
ANISH MISHRA said:
9 years ago
A train leaves P for Q; at the same time another train leaves Q for P. The trains meet after 6 hours, the train from P and Q having travelled 8 km per hour more than the other. If the distance from P and Q is 528 km, the speed of train from P and Q in km/hour is.
Please solve this?
Please solve this?
Mohit said:
1 decade ago
Let 't' b the time in hrs the two trains meet. Then distance traveled by 1st train is 20t and distance.
Traveled by 2nd train is 25 (t-1). Because 2nd train run after 1hr of 1st train.
Total distance = 110 km = 20t+25(t-1).
Solving we get t = 3hr. 7 a.m.+3hr = 10 a.m.
Traveled by 2nd train is 25 (t-1). Because 2nd train run after 1hr of 1st train.
Total distance = 110 km = 20t+25(t-1).
Solving we get t = 3hr. 7 a.m.+3hr = 10 a.m.
Bhoopesh Choudhary said:
1 decade ago
The answer of this question is incorrect if the B train start at 8am and by the speed 25km\hr then it will cover the distance of 50km in next 2 hours but the train A will cove the distance of 60km in next 3 hour by the peed of 20km\hr.
So both can be meet at 10 a.m.
So both can be meet at 10 a.m.
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