Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 30)
30.
Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
Answer: Option
Explanation:
Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
20x + 25(x - 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.
Discussion:
92 comments Page 9 of 10.
Anna said:
7 years ago
Thank you very much @Yuvaraj.
Poojitha said:
1 decade ago
How is it 20x+25(x-1) = 110?
Erererer said:
1 decade ago
X=3 how it convet to 10 am
Shri said:
2 decades ago
Why (x-1) term is used ?
Praveen_Nayak said:
7 years ago
Thank you @Manish Dabhi.
Gokul said:
1 decade ago
How 20x + 25(x-1) = 110?
Arun said:
1 decade ago
Why we use x-1 not x+1?
Joicy said:
1 decade ago
Why (X-1) term is used?
Swasti said:
8 years ago
How this 3 hr comes?
Knn said:
1 decade ago
Yuvraj. Cool answer!
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