Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 26)
26.
Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?
Answer: Option
Explanation:
| Relative speed = (40 - 20) km/hr = |  |
20 x | 5 |  |
m/sec = | |
50 | |
m/sec. |
| 18 | 9 |
 Length of faster train = |
|
50 | x 5 | |
m = | 250 | m = 27 | 7 | m. |
| 9 | 9 | 9 |
Discussion:
72 comments Page 6 of 8.
Hrushi said:
8 years ago
Please explain clearly. Why we ignore the length of the slow train?
Mj pala said:
1 decade ago
If the question is to find the length of the slower train, then?
Antrinitz singh said:
1 decade ago
I can't understand anything can anyone explain with formula.
Sunny said:
1 decade ago
Please can anyone tell me the length of the slower train?
Rohit Parmar said:
6 years ago
How to simplify 250/9 to 27*7/9?
Please explain clearly.
Please explain clearly.
Madhusudhan said:
7 years ago
How to simplify 250/9 to 27*7/9? Please explain clearly.
Sagar said:
4 years ago
Why we don't count two train lengths? Anyone explain me.
(6)
Deepak rawat said:
9 years ago
How to convert 250/9 to mixed fraction? Please explain.
Gargi said:
1 decade ago
Hey guys Haritha was right! It's also not clear to me.
Manil Shylla said:
7 years ago
Please explain me with a simple step how we got 250/9?
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