Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 26)
26.
Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?
Answer: Option
Explanation:
| Relative speed = (40 - 20) km/hr = |  |
20 x | 5 |  |
m/sec = | |
50 | |
m/sec. |
| 18 | 9 |
 Length of faster train = |
|
50 | x 5 | |
m = | 250 | m = 27 | 7 | m. |
| 9 | 9 | 9 |
Discussion:
72 comments Page 5 of 8.
Sindhu said:
1 decade ago
If the two trains are moving in the same direction their relative speeds are subtracted.
Nidhi said:
1 decade ago
Can anybody tell me that, then how can we calculate the length of the slower train?
Shweta said:
1 decade ago
Can anyone tell me when we have to add relative speed and when we have to subtract?
Suman CKP said:
1 decade ago
And Suppose someone ask the speed of slower train then what will be do? Not clear?
Budhiram said:
9 years ago
I also agree with you @Haritha.
It is not given that, where the man is sitting.
It is not given that, where the man is sitting.
Radha Krishna said:
1 year ago
What to do if asked length of a slower train? Anyone, please explain to me.
(7)
Shikha Rajput said:
2 years ago
Can someone explain why we take 5/18 in the km/hr? I am not getting it.
(4)
Shri said:
6 years ago
@Shital.
It is a mixed fraction method, 27 * 9 = 243.
243 + 7 = 250.
It is a mixed fraction method, 27 * 9 = 243.
243 + 7 = 250.
Chaitanyasri said:
9 years ago
Can anyone please explain how to calculate the length of slower train?
Ananth said:
6 years ago
Divide 250 by 9. The Remainder * Quotient/Divisor rule then follows.
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