Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 26)
26.
Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?
23 m
23 2 m
9
27 7 m
9
29 m
Answer: Option
Explanation:

Relative speed = (40 - 20) km/hr = ( 20 x 5 ( m/sec = ( 50 ( m/sec.
18 9

Therefore Length of faster train = ( 50 x 5 ( m = 250 m = 27 7 m.
9 9 9

Discussion:
72 comments Page 4 of 8.

Wangchuk said:   1 decade ago
According to formula relative speed is added when two train are moving in opposite direction and is subtracted in same direction.

Kanishk jain said:   7 years ago
Actually, it means that the length of the faster train relative to the slower train.

That's why the answer is 250/9.

Vishnu said:   9 years ago
250/9 ==>we get.

Quotient = 27, Remainder = 7.
Then it will be in form quotient (remainder/divisor).

ie, 27 7/9.

Sunny said:   1 decade ago
Here also the faster train crossing the slower train hence we get the length of 2 trains, not the faster train.

Swati said:   8 years ago
Why do we ignore the length of the slower train, Is it because the place where the man is sitting is not fixed?

Grish said:   1 decade ago
The position of man is supposed to be ignore. It's a confusing element. Anyway the speed of slower train?

Shwetha said:   1 decade ago
Hey can anyone tell me why we have to take relative speed. When question is regarding fast train length?

Shashi said:   7 years ago
Rather than crossing man, if they asked the length of the slower train, then what will be the method?

Siddarth said:   3 years ago
250 /9 = 27.777777778 means then how to convert it into 27*7/9?

Please explain in detail.
(1)

Bhavya said:   1 decade ago
Relative speed =40-20= 20 is okay after why we multiplied with 5/18, and wt is that 5/18?


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