Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 26)
26.
Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?
Answer: Option
Explanation:
| Relative speed = (40 - 20) km/hr = |  |
20 x | 5 |  |
m/sec = | |
50 | |
m/sec. |
| 18 | 9 |
 Length of faster train = |
|
50 | x 5 | |
m = | 250 | m = 27 | 7 | m. |
| 9 | 9 | 9 |
Discussion:
72 comments Page 7 of 8.
M.vishwa Mohawk reddy said:
6 years ago
How came 27 7/9? I am not getting, Please explain.
Tatikonda Dinesh said:
6 years ago
How to came 27 7/9?
Anybody, Please explain.
Anybody, Please explain.
Qasim said:
1 decade ago
Thanks ram. That one is really good example.
Shital said:
6 years ago
Please, explain this how 250/9 to 27 * 7/9?
(3)
Harpreet said:
1 decade ago
What would be the length of slower train?
Haritha said:
1 decade ago
Could anyone please explain me clearly?
Sadik ali said:
1 decade ago
How can we find speed of slower train?
Alu said:
1 decade ago
What is that 18 denoting to in 5/18?
Azim said:
9 years ago
Consider the slower train as a man.
Pardhu said:
8 years ago
Nice explanation, thank you all.
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