Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 25)
25.
A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
48 km/hr
54 km/hr
66 km/hr
82 km/hr
Answer: Option
Explanation:

Let the speed of the second train be x km/hr.

Relative speed = (x + 50) km/hr
= [ (x + 50) x 5 ] m/sec
18
= [ 250 + 5x ] m/sec.
18

Distance covered = (108 + 112) = 220 m.

Therefore 220 = 6
( 250 + 5x (
18

=> 250 + 5x = 660

=> x = 82 km/hr.

Discussion:
77 comments Page 6 of 8.

Soumitra Das said:   9 years ago
Sorry I make a mistake in my last comment.

D = 108 + 112 = 120.
Converting the speed of 1st Train = 50x 5/18 m/s.
Let the speed of 2nd Train= V m/s.

We get,

220/ (50x 5/18) + V = 6 sec.

=> 220= 6x(250+18V)/18,
=> 220=(250+18V)/3,
=>660= 250+18V,
=>18V=410,
=> V= 410/18 m/s.

Converting the speed of the second Train we Get,
=> (410/18) x (18/5).
=> 82 Kmph.

This is the right answer

Ashwin kumar said:   9 years ago
@Ashok.

How you get 220/250 + 5x/18?

Sriram said:   8 years ago
We have got v (kmph) if it had been v * 5/18 then we would have gotten speed in m/s.

Gangani said:   7 years ago
First take 220/6=36.66 m/s.

Now convert into km/h so 132km/h.
and minus 50km/h from 132 - 50 = 82km/h.
Thanks.

Nileshshelar said:   7 years ago
(Total distance covered) ÷ (net speed) = time.
Mtrs/(mtr/sec) = sec.
220/(50+x) * 5/18=6,
So x=82.

But the unit is now mtr/sec because all we have converted into mtrs and seconds.

Gopal sunar said:   7 years ago
Thank you @Soumitra Das.

Nagesh said:   6 years ago
Thank you @Das.

Arkadev said:   6 years ago
Relative speed =220/6 * 18/5=132.
Second trains speed =132-50 = 80.

Prity sahay said:   6 years ago
If everything is converted into m/s then the answer will also be 82m/s not 82 km/hr.
(1)

Prem said:   6 years ago
I agree with you. @Prity.


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