Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 25)
25.
A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
Answer: Option
Explanation:
Let the speed of the second train be x km/hr.
| Relative speed | = (x + 50) km/hr | |||||||
|
||||||||
|
![]](/_files/images/aptitude/1-sym-cbracket-h1.gif)
Distance covered = (108 + 112) = 220 m.
 |
220 | = 6 | ||
|
250 + 5x = 660
x = 82 km/hr.
Discussion:
77 comments Page 8 of 8.
Sagar said:
4 years ago
@All.
First, we are assumed as X in km/hr, but we are applying the formula convert into M/S it is applicable for RELATIVE SPEED=(X+50).
It is not applicable for Assuming X, so the final answer is in KM/H.
First, we are assumed as X in km/hr, but we are applying the formula convert into M/S it is applicable for RELATIVE SPEED=(X+50).
It is not applicable for Assuming X, so the final answer is in KM/H.
(5)
Nagesh said:
3 years ago
6 = 220 then,
36 = (x+50)*10.
After cross multiple;
6*22 = X + 50.
X = 82.
36 = (x+50)*10.
After cross multiple;
6*22 = X + 50.
X = 82.
GAISINREI said:
3 years ago
First convert km/hr in m/secs,
x= 410/18 m/secs.
for km/hr.
41O/18 * 18/5 = 82km/hr.
x= 410/18 m/secs.
for km/hr.
41O/18 * 18/5 = 82km/hr.
Chanchal Tathe said:
3 years ago
@Ambika.
Good explanation. Thanks.
Good explanation. Thanks.
(3)
M umayal said:
2 years ago
Here is the simplest form that you can understand.
Since the two train travel in opp directions, add both speeds. the speed of one train is given, let the speed of another train be x.
Speed=x+50 km/hr.
The relative distance = 108 + 112 = 220 m.
Time = 6 seconds.
Speed = distance/time.
x+50 = 220/6 m/s
x+50 = 110/3 *18/5(to convert m/s to km/hr ,since the answer required in km/hr)
x+50 = 132,
x = 82 km/hr.
Since the two train travel in opp directions, add both speeds. the speed of one train is given, let the speed of another train be x.
Speed=x+50 km/hr.
The relative distance = 108 + 112 = 220 m.
Time = 6 seconds.
Speed = distance/time.
x+50 = 220/6 m/s
x+50 = 110/3 *18/5(to convert m/s to km/hr ,since the answer required in km/hr)
x+50 = 132,
x = 82 km/hr.
(40)
Sharmila said:
2 years ago
Can we convert 50 km/hr into m/s and add the speed of other trains as they are in opposite directions?
Can anyone explain me?
Can anyone explain me?
(3)
Purushottam said:
2 months ago
It's (220/6*18/5) - 50 = 82km/h.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers