Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 25)
25.
A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
Answer: Option
Explanation:
Let the speed of the second train be x km/hr.
Relative speed | = (x + 50) km/hr | |||||||
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Distance covered = (108 + 112) = 220 m.
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220 | = 6 | ||
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250 + 5x = 660
x = 82 km/hr.
Discussion:
77 comments Page 4 of 8.
Sujai Matta said:
1 decade ago
Let me explain in details.
First train length, a = 108m.
Its speed, u = 50 km/hr = 50*5/18 m/sec= 125/9 m/sec.
Second train length,b = 112m.
Let, its speed, v = x m/sec.
Each other crosses in 6 sec.
So, we have, t= ((a+b)/(u+v)).
6= ((108+112)/((125/9)+x)).
(125/9)+x = 220/6.
x = (220/6)-(125/9)= 205/9 m/sec.
Converting in km/hr.
(205/9)*(18/5) = 82 km/hr.
First train length, a = 108m.
Its speed, u = 50 km/hr = 50*5/18 m/sec= 125/9 m/sec.
Second train length,b = 112m.
Let, its speed, v = x m/sec.
Each other crosses in 6 sec.
So, we have, t= ((a+b)/(u+v)).
6= ((108+112)/((125/9)+x)).
(125/9)+x = 220/6.
x = (220/6)-(125/9)= 205/9 m/sec.
Converting in km/hr.
(205/9)*(18/5) = 82 km/hr.
Student said:
1 decade ago
Well I have a doubt, how did you get 5/18? Sorry if it is a stupid question!
Rocky said:
1 decade ago
I would like to bring this error to your notice that it is 82 m/s and not 82 km/hr.
Sathish said:
1 decade ago
Hai I have another option.
D = 220.
S = 50 kmph.
T = 6.
Other speed = x.
So speed = (x+50)*5/18.
T = D/S. Find T subtract 50 that's answer = 82 kmph.
D = 220.
S = 50 kmph.
T = 6.
Other speed = x.
So speed = (x+50)*5/18.
T = D/S. Find T subtract 50 that's answer = 82 kmph.
SathyaPriya said:
1 decade ago
Let me explain in detail.
Let the speed of second train be xkm/hr.
Therefore, relative speed = (50+x)km/hr (since it is opposite direction the speeds should be added). Then no need to confuse yourself by converting the speed to m/s.
Take it as it is, so as to get our answer in km/hr (as the given options are in km/hr). Now just convert the distances 108m & 112m into km/hr.
So add the distances & then convert it.
D = 108+112 = 220m = (220 x 18/5) = 792km/hr.
So now distance is in km/hr.
T = D/S.
6 = 792/(x+50).
6x+300 = 792.
Therefore x = 82km/hr.
Let the speed of second train be xkm/hr.
Therefore, relative speed = (50+x)km/hr (since it is opposite direction the speeds should be added). Then no need to confuse yourself by converting the speed to m/s.
Take it as it is, so as to get our answer in km/hr (as the given options are in km/hr). Now just convert the distances 108m & 112m into km/hr.
So add the distances & then convert it.
D = 108+112 = 220m = (220 x 18/5) = 792km/hr.
So now distance is in km/hr.
T = D/S.
6 = 792/(x+50).
6x+300 = 792.
Therefore x = 82km/hr.
Shree said:
1 decade ago
(108+112)/6 = 50 + x.
(220/6)*(18/5) = 50 + x.
132 = 50 + x.
x = 82 Km/hr.
(220/6)*(18/5) = 50 + x.
132 = 50 + x.
x = 82 Km/hr.
Prathiba said:
1 decade ago
How does 660 comes in last step?
Rishav kumar said:
10 years ago
Yes answer is correct but checking through reverse process.
Let x = 82 km/h and we have find time to cross each other. Then then the answer will come 6 sec. So it is correct.
Let x = 82 km/h and we have find time to cross each other. Then then the answer will come 6 sec. So it is correct.
Arun said:
10 years ago
Relative speed = x+50 km/hr.
6 = 220/(x+50)*(5/18).
5/3 = 220/(x+50).
x+50 = 132.
x = 82 m/sec.
Please explain, how km/hr.
And one more method.
6/3600= (220*10^-3)/(x+50).
x+50 = 600*0.22.
x = 142-50.
x = 92 km/hr.
Now I am totally confused. Please help.
6 = 220/(x+50)*(5/18).
5/3 = 220/(x+50).
x+50 = 132.
x = 82 m/sec.
Please explain, how km/hr.
And one more method.
6/3600= (220*10^-3)/(x+50).
x+50 = 600*0.22.
x = 142-50.
x = 92 km/hr.
Now I am totally confused. Please help.
(1)
Sajan said:
10 years ago
Distance = (220/1000) km {Want to convert meter into kilometer).
Time = (6/3600) seconds {Second into hours - one hour has 3600 seconds}.
Distance/Time = Speed.
= (220/1000)/(6/3600) = x+50 km {Opposite speed should be added).
Now without converting, follow normally:
220/6*3600 = (50+x) speed (If goes 220 m within 6 seconds, what is the distance per hour or 3600 seconds).
132000 m per hour = (50+x).
So, 132 kilometer = (50+x).
x = 132-50 = 82.
Time = (6/3600) seconds {Second into hours - one hour has 3600 seconds}.
Distance/Time = Speed.
= (220/1000)/(6/3600) = x+50 km {Opposite speed should be added).
Now without converting, follow normally:
220/6*3600 = (50+x) speed (If goes 220 m within 6 seconds, what is the distance per hour or 3600 seconds).
132000 m per hour = (50+x).
So, 132 kilometer = (50+x).
x = 132-50 = 82.
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