Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 22)
22.
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
Answer: Option
Explanation:
| Relative speed = | = (45 + 30) km/hr | |||||||
|
||||||||
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We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
 Required time = |
 |
500 x | 6 |  |
= 24 sec. |
| 125 |
Discussion:
81 comments Page 4 of 9.
Baseer said:
1 decade ago
5/18 came from? Can some one tell me please.
Swati said:
1 decade ago
Nice one. We have to calculate for drive i.e. for man, not for train.
Shekhar said:
1 decade ago
Instead of DRIVER if whole length of faster train then how to calculate?
AMAR said:
10 years ago
In that condition, take total length both train.
i.e 1000/t = (75*5/18).
We get the answer = 48 s.
i.e 1000/t = (75*5/18).
We get the answer = 48 s.
Ashu baba said:
10 years ago
Conclusion is faster or slower answer will be same (examiner troll).
Alice said:
10 years ago
This s a good tricky question. I too made a mistake for the first time. But now I got it. Thank you for the explanation.
Ankit said:
10 years ago
The question here is find the time when driver meet not find the time when the train crosses each other.
Xavi said:
9 years ago
Yes, 24sec is the correct answer.
Because the math required us to find out only the passing time of the driver of the slower train.
Because the math required us to find out only the passing time of the driver of the slower train.
Manish said:
9 years ago
I am not getting understand where we got 5/18.
Keerthi srihari said:
9 years ago
Here there is asking only time taken by slower train to cross a faster train here assume the driver of the faster train is considered as a static object so we take only slower train distance.
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