Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 22)
22.
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
Answer: Option
Explanation:
| Relative speed = | = (45 + 30) km/hr | |||||||
|
||||||||
|
We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
 Required time = |
 |
500 x | 6 |  |
= 24 sec. |
| 125 |
Discussion:
81 comments Page 3 of 9.
Msvignesh viki said:
1 decade ago
d = s/t.
(500+500) = distance = 1000.
Speed = 45kmph+30kmph = 75kmph.
Then convert it in to metre = 75*5/18 = 20.833333.
t = d/s = 1000/20.83333 = 48sec.
Then 2x(two train) = 48sec ; x = 48/2 => x = 24sec for each train.
(500+500) = distance = 1000.
Speed = 45kmph+30kmph = 75kmph.
Then convert it in to metre = 75*5/18 = 20.833333.
t = d/s = 1000/20.83333 = 48sec.
Then 2x(two train) = 48sec ; x = 48/2 => x = 24sec for each train.
Tejaswini said:
9 years ago
Problem no.9 is same only the length of trains is different. There they have considered the length of both trains. Then why in this problem they have considered the length of one train?
Please tell me the reason.
Please tell me the reason.
Keerthi srihari said:
9 years ago
Here there is asking only time taken by slower train to cross a faster train here assume the driver of the faster train is considered as a static object so we take only slower train distance.
Hariprasanna V said:
1 month ago
@All.
I am also confused about the 500, but we need to carefully read the question; they mentioned that the slower train crosses the driver, not the faster train.
Correct me, if I am wrong.
I am also confused about the 500, but we need to carefully read the question; they mentioned that the slower train crosses the driver, not the faster train.
Correct me, if I am wrong.
Samarya kapoor said:
9 years ago
@All.
Answer is incorrect. It should be 48 instead of 24. If the given answer is correct then look at question number 9 the same question with different value then q. 9 is incorrect.
Answer is incorrect. It should be 48 instead of 24. If the given answer is correct then look at question number 9 the same question with different value then q. 9 is incorrect.
Veerappan said:
1 decade ago
I accept @Durgesh, because he said well.
Faster train driver can be considered as an object like standing pole on station, slower train to pass a faster train driver is 500/75*5/18.
Faster train driver can be considered as an object like standing pole on station, slower train to pass a faster train driver is 500/75*5/18.
Dhanraj said:
6 years ago
No, it is not 48 sec, Check It's mentioned to find the time to cross the fast train driver, so consider this as point or pole example and solve using the length of a single train.
(2)
Shivank said:
9 years ago
Here we are assuming that driver is in front of the train, but generally, drivers are not in front and if the location of the driver is mentioned question will become more tricky.
Pawan yadav said:
8 years ago
Yes, friends.
Because the length of train add in both condition same direction or opposite direction only speed is a minus in the same direction and add opposite direction.
Because the length of train add in both condition same direction or opposite direction only speed is a minus in the same direction and add opposite direction.
Nanda Kishor said:
8 years ago
@Raju.
In this problem, the relative speed is 75km/hr.
And to find the answer we have to convert the speed into m/s. So(75*5/18= 125/6m/s).
Hope that this will help you.
In this problem, the relative speed is 75km/hr.
And to find the answer we have to convert the speed into m/s. So(75*5/18= 125/6m/s).
Hope that this will help you.
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