Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 21)
21.
How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Answer: Option
Explanation:
Speed of the train relative to man | = (63 - 3) km/hr | |||||||
= 60 km/hr | ||||||||
|
||||||||
|
||||||||
![]() |
|
|||||||
= 30 sec. |
Discussion:
44 comments Page 4 of 5.
Shashank said:
1 decade ago
@Samuel then relative speed gets added up. Its (60+3) instead of (60-3).
Samuel said:
1 decade ago
What if the man was going in the opposite direction of the train?
Subhrendu said:
1 decade ago
We are dividing distance (500) by speed (50/3). So, 50/3 is in the denominator and it becomes 3/50 when we are multiplying.
Raj said:
1 decade ago
Is it same for time taken by the man to cross the train ?
Amir said:
1 decade ago
Can anyone explain me why 50/3 is inverted while calculating the time as 500 * 3/50 why not 500* 50/3 ?
John said:
1 decade ago
How does 60 x 5 m/sec become = 50 m/sec.
18 3
18 3
HARMEET said:
1 decade ago
1KM=1000 METERS AND 1 HRS= 3600 SECONDS,
SO, DISTANCE/TIME= 1KM/1HOUR
1KM/1HOUR=1000 METERS/3600 SECONDS= 5/18.......
UNDERSTAND?????????
SO, DISTANCE/TIME= 1KM/1HOUR
1KM/1HOUR=1000 METERS/3600 SECONDS= 5/18.......
UNDERSTAND?????????
Akshay said:
1 decade ago
How did you derive 5/18? can somebody explain?
Ravi kumar said:
1 decade ago
Train n man moving same direction n train crosses the man so we calculate speed in same direction, so are. Speed is 63-3=60.
Lalitha said:
1 decade ago
We take 60-3 because man and train are going in same direction thats why we need to do subtraction.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers