Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 21)
21.
How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Answer: Option
Explanation:
| Speed of the train relative to man | = (63 - 3) km/hr | |||||||
| = 60 km/hr | ||||||||
|
||||||||
|
||||||||
 Time taken to pass the man |
|
|||||||
| = 30 sec. |
Discussion:
44 comments Page 1 of 5.
Selva said:
1 decade ago
I wanna know how they calculate the speed of the train?
Varun sen said:
1 decade ago
Why wouldn't the speed added here when man and train are approaches each other (60+6) = 66 ?
Jelli said:
1 decade ago
here the prob is to find the time=?
wkt
z=(a+b)/(u-v)
here a=500,b=0(bcz it's man,pole=0),u=60kmph,v=3kmph
then z=30sec
wkt
z=(a+b)/(u-v)
here a=500,b=0(bcz it's man,pole=0),u=60kmph,v=3kmph
then z=30sec
Megha said:
1 decade ago
Why we do this (63-3) instead of (63+3) ?
Lalitha said:
1 decade ago
We take 60-3 because man and train are going in same direction thats why we need to do subtraction.
Ravi kumar said:
1 decade ago
Train n man moving same direction n train crosses the man so we calculate speed in same direction, so are. Speed is 63-3=60.
Akshay said:
1 decade ago
How did you derive 5/18? can somebody explain?
HARMEET said:
1 decade ago
1KM=1000 METERS AND 1 HRS= 3600 SECONDS,
SO, DISTANCE/TIME= 1KM/1HOUR
1KM/1HOUR=1000 METERS/3600 SECONDS= 5/18.......
UNDERSTAND?????????
SO, DISTANCE/TIME= 1KM/1HOUR
1KM/1HOUR=1000 METERS/3600 SECONDS= 5/18.......
UNDERSTAND?????????
John said:
1 decade ago
How does 60 x 5 m/sec become = 50 m/sec.
18 3
18 3
Amir said:
1 decade ago
Can anyone explain me why 50/3 is inverted while calculating the time as 500 * 3/50 why not 500* 50/3 ?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers