Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 21)
21.
How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Answer: Option
Explanation:
Speed of the train relative to man | = (63 - 3) km/hr | |||||||
= 60 km/hr | ||||||||
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= 30 sec. |
Discussion:
44 comments Page 2 of 5.
Nisar said:
1 decade ago
Speed of train in m/s = 17.5.
Time taken to cross a man = x.
Speed of man in m/s = 0.833.
17.5*x = 500 + 0.833*x.
16.66 x = 500.
x = 30.00sec.
Time taken to cross a man = x.
Speed of man in m/s = 0.833.
17.5*x = 500 + 0.833*x.
16.66 x = 500.
x = 30.00sec.
HARMEET said:
1 decade ago
1KM=1000 METERS AND 1 HRS= 3600 SECONDS,
SO, DISTANCE/TIME= 1KM/1HOUR
1KM/1HOUR=1000 METERS/3600 SECONDS= 5/18.......
UNDERSTAND?????????
SO, DISTANCE/TIME= 1KM/1HOUR
1KM/1HOUR=1000 METERS/3600 SECONDS= 5/18.......
UNDERSTAND?????????
Sapna said:
7 years ago
It's (63-3) because they both are moving in the same direction. If they are opposite to each other at that time we add the relative speed.
(1)
Ravi kumar said:
1 decade ago
Train n man moving same direction n train crosses the man so we calculate speed in same direction, so are. Speed is 63-3=60.
Subhrendu said:
1 decade ago
We are dividing distance (500) by speed (50/3). So, 50/3 is in the denominator and it becomes 3/50 when we are multiplying.
Jelli said:
1 decade ago
here the prob is to find the time=?
wkt
z=(a+b)/(u-v)
here a=500,b=0(bcz it's man,pole=0),u=60kmph,v=3kmph
then z=30sec
wkt
z=(a+b)/(u-v)
here a=500,b=0(bcz it's man,pole=0),u=60kmph,v=3kmph
then z=30sec
Sarang said:
7 years ago
Distance =speed *time.
500=60-3km/h*time,
500=60*5/18*time,
500=60*.277*time,
500=16.62*time,
Time=500/16.62=30s.
500=60-3km/h*time,
500=60*5/18*time,
500=60*.277*time,
500=16.62*time,
Time=500/16.62=30s.
Amir said:
1 decade ago
Can anyone explain me why 50/3 is inverted while calculating the time as 500 * 3/50 why not 500* 50/3 ?
VINAYAK PB said:
9 years ago
First of all, calculate 1m per second that is 60000/3600 = 16.6m/s.
So for 500m it, 500/16.6 = 30sec.
So for 500m it, 500/16.6 = 30sec.
Lalitha said:
1 decade ago
We take 60-3 because man and train are going in same direction thats why we need to do subtraction.
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