Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 21)
21.
How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Answer: Option
Explanation:
| Speed of the train relative to man | = (63 - 3) km/hr | |||||||
| = 60 km/hr | ||||||||
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 Time taken to pass the man |
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| = 30 sec. |
Discussion:
44 comments Page 2 of 5.
Kiran said:
6 years ago
It's 500 * 50\3.
= 500*3/50
= 10 * 3.
= 30sec.
= 500*3/50
= 10 * 3.
= 30sec.
Vijay said:
7 years ago
Length of the train = 500m
Speed of the man = 3km/hr
Speed of the train = 63km/hr
Relative speed = 63-3 = 60km/hr = 60 * 5/18 = 50/3(m/s).
Let x be the sec,
500/x = 50/3,
X = 30sec.
Speed of the man = 3km/hr
Speed of the train = 63km/hr
Relative speed = 63-3 = 60km/hr = 60 * 5/18 = 50/3(m/s).
Let x be the sec,
500/x = 50/3,
X = 30sec.
Niyati said:
1 decade ago
Why take 5/18?
Jeni said:
7 years ago
Why we take (63-3) please explain anyone?
Akil Prakash said:
8 years ago
Instead of 50/3 why we use 3/50?
Sarang said:
8 years ago
Distance =speed *time.
500=60-3km/h*time,
500=60*5/18*time,
500=60*.277*time,
500=16.62*time,
Time=500/16.62=30s.
500=60-3km/h*time,
500=60*5/18*time,
500=60*.277*time,
500=16.62*time,
Time=500/16.62=30s.
Sonam Lhadon said:
5 years ago
How it 50/3 becomes 3/50?
Anyone, please explain it.
Anyone, please explain it.
Raghu said:
9 years ago
Here why we didn't add 500 to the distance, total distance = 500 + 500 = 10000?
Please explain.
Please explain.
Aliza Mir said:
10 years ago
Here speeds of train and man are accordingly subtracted because the reference point.
i.e. man is not stationary. Had it been stationary the formula to be applied would have been u - v m/sec. Since, this is not the case scenario so the formula applied is u= v - x m/sec.
i.e. man is not stationary. Had it been stationary the formula to be applied would have been u - v m/sec. Since, this is not the case scenario so the formula applied is u= v - x m/sec.
VINAYAK PB said:
10 years ago
First of all, calculate 1m per second that is 60000/3600 = 16.6m/s.
So for 500m it, 500/16.6 = 30sec.
So for 500m it, 500/16.6 = 30sec.
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