Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 21)
21.
How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Answer: Option
Explanation:
| Speed of the train relative to man | = (63 - 3) km/hr | |||||||
| = 60 km/hr | ||||||||
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 Time taken to pass the man |
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| = 30 sec. |
Discussion:
44 comments Page 2 of 5.
Mahir said:
6 years ago
@Jeni.
The train and the man both were going in the same direction and that means by one hour when the train will have been going 63 km and the man 3km. So, the net distance will be 63-3 = 60km.
If they were approaching from the opposite direction, then we had to add up their speed.
The train and the man both were going in the same direction and that means by one hour when the train will have been going 63 km and the man 3km. So, the net distance will be 63-3 = 60km.
If they were approaching from the opposite direction, then we had to add up their speed.
(1)
Jeni said:
7 years ago
Why we take (63-3) please explain anyone?
Sapna said:
7 years ago
It's (63-3) because they both are moving in the same direction. If they are opposite to each other at that time we add the relative speed.
(1)
Akil Prakash said:
7 years ago
Instead of 50/3 why we use 3/50?
Sarang said:
7 years ago
Distance =speed *time.
500=60-3km/h*time,
500=60*5/18*time,
500=60*.277*time,
500=16.62*time,
Time=500/16.62=30s.
500=60-3km/h*time,
500=60*5/18*time,
500=60*.277*time,
500=16.62*time,
Time=500/16.62=30s.
Naresh said:
7 years ago
Instead of subtracting 63-3, I first converted 63kmph and 3kmph to its equivalent m/s and then I subtracted. The answer I got was not equal to 60*(5/18). Why? Can someone explain?
(1)
Raghu said:
8 years ago
Here why we didn't add 500 to the distance, total distance = 500 + 500 = 10000?
Please explain.
Please explain.
VINAYAK PB said:
9 years ago
First of all, calculate 1m per second that is 60000/3600 = 16.6m/s.
So for 500m it, 500/16.6 = 30sec.
So for 500m it, 500/16.6 = 30sec.
Aliza Mir said:
9 years ago
Here speeds of train and man are accordingly subtracted because the reference point.
i.e. man is not stationary. Had it been stationary the formula to be applied would have been u - v m/sec. Since, this is not the case scenario so the formula applied is u= v - x m/sec.
i.e. man is not stationary. Had it been stationary the formula to be applied would have been u - v m/sec. Since, this is not the case scenario so the formula applied is u= v - x m/sec.
Hariharan.p(sphari23) said:
9 years ago
Same direction man&train moving = a+b/u-v.
500/63-3*5/18 m/sec.
=> 30 sec.
500/63-3*5/18 m/sec.
=> 30 sec.
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