Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 20)

Problems on Trains

20.

A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?

69.5 km/hr

70 km/hr

79 km/hr

79.2 km/hr

Answer: Option

Explanation:

Let the length of the train be x metres and its speed by y m/sec.

Then,	x	= 8 x = 8y
	y

Now,	x + 264	= y
	20

8y + 264 = 20y

y = 22.

Speed = 22 m/sec =		22 x	18		km/hr = 79.2 km/hr.
			5

Discussion:

46 comments Page 5 of 5.

Sainpal said: 7 years ago

Nice method. Thanks @Diksha Rajput.

Laxman biradar said: 7 years ago

Nice explanation @Gaurav Reddy.

Neelam said: 1 decade ago

How you people got 3x = 528?

Vasu said: 5 years ago

Thank you @Randhir.

Gai3 said: 1 decade ago

Thanks @Nagarjun.

Prashant said: 6 years ago

Thanks @Randhir.

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