Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 20)
20.
A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?
Answer: Option
Explanation:
Let the length of the train be x metres and its speed by y m/sec.
| Then, | x | = 8  x = 8y |
| y |
| Now, | x + 264 | = y |
| 20 |
8y + 264 = 20y
y = 22.
 Speed = 22 m/sec = |
 |
22 x | 18 |  |
km/hr = 79.2 km/hr. |
| 5 |
Discussion:
46 comments Page 4 of 5.
Priya said:
1 decade ago
Hi, I didn't understand the solution. Can someone explain step by step ?
PAKA RAKESH said:
1 decade ago
Simply take time(20-8)=12 secs
speed=264*(18/5)=79.2km/hr
speed=264*(18/5)=79.2km/hr
Rakesh said:
1 decade ago
22meters*60(sec)=1.32km/min
1.32*60(mins)=79.2km/hr
1.32*60(mins)=79.2km/hr
Aishuy said:
7 years ago
How will make 22*18/5? Please explain this step.
Hussain said:
1 decade ago
How we got 18/5? Can any one explain me clearly?
Anjani said:
10 years ago
Why we take 8 sec why don't we consider 20 sec?
Mani said:
1 decade ago
Please any one explain why we divide 176/8?
Shambhu said:
7 years ago
Hi, I can't understand please explain me.
Rana sk said:
8 years ago
20-8=12,
264÷12=22
22*18÷5=79.2.
264÷12=22
22*18÷5=79.2.
Sanchita said:
1 decade ago
Please explain sum one in simple method.
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