Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 20)
20.
A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?
69.5 km/hr
70 km/hr
79 km/hr
79.2 km/hr
Answer: Option
Explanation:

Let the length of the train be x metres and its speed by y m/sec.

Then, x = 8     =>     x = 8y
y

Now, x + 264 = y
20

=> 8y + 264 = 20y

=> y = 22.

Therefore Speed = 22 m/sec = ( 22 x 18 ( km/hr = 79.2 km/hr.
5

Discussion:
46 comments Page 1 of 5.

Ravibhai said:   2 years ago
Simple:

Time = Distance/Speed.
Speed = Distance/Time.
= 264/(20-8)×5/18.
= 79.2km/h.
(18)

Vishnu said:   3 years ago
D = 264m,
T1 = 8 s,
T2 = 20s,
T = 20-8,
T = 12sec,

S = D/T.
S= 264/12,
S= 22 m/s,
S * 5/18 = 22.
S = 22 * 18/5.
S = 79.2 km/hr.
(24)

PRIYADARSHI PRATTYULYA KUMAR BHATTA said:   4 years ago
Simply the solution is;

12sec = 264
1sec = 264/12 = 22.
i.e. speed is 22 m / sec.
So we convert it into km/hr.
That is 22*18/5 = 79.2 km/hr.
(19)

Vasu said:   5 years ago
Thank you @Randhir.

Debashis said:   6 years ago
****Simple technique************

let's length of train = x.
Sp. of train = x/8.
Mathematically, (x+264)/20 = x/8.
or, x=176 m.

Now, speed of train = (176/8)*(18/5) = 79.2 km/hr.
(7)

Govindraj said:   6 years ago
Hi all,

22 m/s = 22*1000/3600 km/hr = 6.1 km/hr.

Let me know if I am wrong.
(2)

Prashant said:   6 years ago
Thanks @Randhir.

Laxman biradar said:   7 years ago
Nice explanation @Gaurav Reddy.

Shambhu said:   7 years ago
Hi, I can't understand please explain me.

Aishuy said:   7 years ago
How will make 22*18/5? Please explain this step.


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