Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 16)
16.
A train travelling at a speed of 75 mph enters a tunnel 31/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?
2.5 min
3 min
3.2 min
3.5 min
Answer: Option
Explanation:

Total distance covered
= ( 7 + 1 ( miles
2 4
= 15 miles.
4

Therefore Time taken
= ( 15 ( hrs
4 x 75
= 1 hrs
20
= ( 1 x 60 ( min.
20
= 3 min.

Discussion:
129 comments Page 7 of 13.

Rahul Bhosale said:   9 years ago
Mph means mile per hour OR meter per hour?

I think mile per hour is correct.

Avii said:   9 years ago
Yeah! the answer will be 3.2 sec.

As it is clearly written from the moment front enter to the moment rear emerge so, twice the length of the train.

Kunal hire said:   9 years ago
How to convert min into an hour? Please anyone explain.

Sanjay singh said:   9 years ago
According to me, the answer is 3.2 min.

Prakhar Mittal said:   9 years ago
It is not clear that the speed is given in which units as Rahul Bhosale asked above.

Nivin said:   9 years ago
I agree with you @Sanjay Singh.

Abi said:   9 years ago
Why finally it convert into hours? Please explain.

Raju Ahmed said:   9 years ago
Total distance covered = 7/2(tunnel) + 1/4(length of train) + 1/4(length of train since the rear part is to be considered emerging) = 4 miles.

So total time taken = (4 miles/75mph ) * 60 mins.
= 3.2 mins.

So the answer is [C].

Appa rao said:   9 years ago
The answer should be option C.

Total distance covered = 7/2(tunnel) + 1/4(length of train) + 1/4(length of train since the rear part is to be considered emerging) = 4 miles.

So total time taken = (4 miles/75mph ) * 60 mins.
= 3.2 mins.

So the answer is option C.

Ajinath khedkar said:   9 years ago
Yes, Option C is the correct answer.


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