Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 16)
16.
A train travelling at a speed of 75 mph enters a tunnel 31/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?
2.5 min
3 min
3.2 min
3.5 min
Answer: Option
Explanation:

Total distance covered
= ( 7 + 1 ( miles
2 4
= 15 miles.
4

Therefore Time taken
= ( 15 ( hrs
4 x 75
= 1 hrs
20
= ( 1 x 60 ( min.
20
= 3 min.

Discussion:
129 comments Page 1 of 13.

Sharan said:   2 decades ago
1mile=?km

Sundar said:   2 decades ago
1 mile = 1.60934 km.

Ghousia said:   2 decades ago
How 15/(4*75) hrs?

Deepti said:   1 decade ago
Time = Distance/ Dpeed.

Speed= 75 mph, distance= 15/4.

ERRER said:   1 decade ago
Explain how 7/2?

Priyavel said:   1 decade ago
@Errer

We convert mixed fraction into proper fraction
( 3*2=6+1=7)

Pasha4u said:   1 decade ago
Please can any one explain it ?

Sree said:   1 decade ago
Please explain clearly how 7/2?

Viswam said:   1 decade ago
See this link: http://www.mathsisfun.com/mixed-fractions.html

Gaurav said:   1 decade ago
I think the total distance = 7/2 + 1/4 + 1/4 = 4 miles as the summation of length of the tunnel, length of train when it enters and length of train when it emerges out should be taken.


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