Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 4)
4.
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
1 : 3
3 : 2
3 : 4
None of these
Answer: Option
Explanation:

Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, length of the first train = 27x metres,

and length of the second train = 17y metres.

27x + 17y = 23
x+ y

27x + 17y = 23x + 23y

4x = 6y

x = 3 .
y 2

Discussion:
237 comments Page 20 of 24.

Askar said:   1 decade ago
:) The simple formula use for this problem is S = v*t.

Het said:   1 decade ago
@Arashan has describe very well with formula of speed.

Sameer said:   2 decades ago
Can anyone explain me how he got this step 4x = 6y ?

Nayana said:   1 decade ago
Thank u sumi i was confused in that step now i got..

Pallavi said:   1 decade ago
Can anyone tell me the formulas for relative speed ?

Sunil said:   10 years ago
Hi @Gokulakisan sorry to say 27+23 = 50 not for 60.

Latz said:   8 years ago
What if both trains will be in the same direction?

Vishnu said:   8 years ago
@Sudhan.

Isn't 27-17 = 10? How do you say it's 6?

ASHIS DAS said:   7 years ago
Agree @Ganapathi.

Please, anyone, give clearance.

Arifshaikh said:   9 years ago
Try the rule of alligation.

It will take 30 sec.


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