Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 4)
4.
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
Answer: Option
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
 |
27x + 17y | = 23 |
| x+ y |
27x + 17y = 23x + 23y
4x = 6y
| |
x | = | 3 | . |
| y | 2 |
Discussion:
233 comments Page 20 of 24.
Sameer said:
1 decade ago
Can anyone explain me how he got this step 4x = 6y ?
Nayana said:
1 decade ago
Thank u sumi i was confused in that step now i got..
Pallavi said:
1 decade ago
Can anyone tell me the formulas for relative speed ?
Sunil said:
10 years ago
Hi @Gokulakisan sorry to say 27+23 = 50 not for 60.
Latz said:
8 years ago
What if both trains will be in the same direction?
Vishnu said:
7 years ago
@Sudhan.
Isn't 27-17 = 10? How do you say it's 6?
Isn't 27-17 = 10? How do you say it's 6?
ASHIS DAS said:
7 years ago
Agree @Ganapathi.
Please, anyone, give clearance.
Please, anyone, give clearance.
Arifshaikh said:
9 years ago
Try the rule of alligation.
It will take 30 sec.
It will take 30 sec.
Sudhan Vybow said:
7 years ago
Make it simple.
27-17 =6 :27-23 =4
6:4 or 3:2.
27-17 =6 :27-23 =4
6:4 or 3:2.
Rohan said:
4 years ago
Can the ratio be 2:3? Anyone explain me, please.
(3)
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